Input interpretation
vanadium(IV) oxide sulfate hydrate | molar mass
Result
Find the molar mass, M, for vanadium(IV) oxide sulfate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: VOSO_4·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 2 O (oxygen) | 6 S (sulfur) | 1 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 2 | 1.008 O (oxygen) | 6 | 15.999 S (sulfur) | 1 | 32.06 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 2.016 g/mol + 95.994 g/mol + 32.06 g/mol + 50.9415 g/mol = 181.01 g/mol
Unit conversion
0.18101 kg/mol (kilograms per mole)
Comparisons
≈ 0.25 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.93 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 181 u (unified atomic mass units) | 181 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 181