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SO3 + Ba(OH)2 = H2O + BaSO4

Input interpretation

SO_3 sulfur trioxide + Ba(OH)_2 barium hydroxide ⟶ H_2O water + BaSO_4 barium sulfate
SO_3 sulfur trioxide + Ba(OH)_2 barium hydroxide ⟶ H_2O water + BaSO_4 barium sulfate

Balanced equation

Balance the chemical equation algebraically: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_3 + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, S, Ba and H: O: | 3 c_1 + 2 c_2 = c_3 + 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 H: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4
Balance the chemical equation algebraically: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_3 + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, S, Ba and H: O: | 3 c_1 + 2 c_2 = c_3 + 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 H: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4

Structures

+ ⟶ +
+ ⟶ +

Names

sulfur trioxide + barium hydroxide ⟶ water + barium sulfate
sulfur trioxide + barium hydroxide ⟶ water + barium sulfate

Equilibrium constant

Construct the equilibrium constant, K, expression for: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 H_2O | 1 | 1 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_3 | 1 | -1 | ([SO3])^(-1) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) H_2O | 1 | 1 | [H2O] BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SO3])^(-1) ([Ba(OH)2])^(-1) [H2O] [BaSO4] = ([H2O] [BaSO4])/([SO3] [Ba(OH)2])
Construct the equilibrium constant, K, expression for: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 H_2O | 1 | 1 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_3 | 1 | -1 | ([SO3])^(-1) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) H_2O | 1 | 1 | [H2O] BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SO3])^(-1) ([Ba(OH)2])^(-1) [H2O] [BaSO4] = ([H2O] [BaSO4])/([SO3] [Ba(OH)2])

Rate of reaction

Construct the rate of reaction expression for: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 H_2O | 1 | 1 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_3 | 1 | -1 | -(Δ[SO3])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[SO3])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = (Δ[H2O])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SO_3 + Ba(OH)_2 ⟶ H_2O + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 H_2O | 1 | 1 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_3 | 1 | -1 | -(Δ[SO3])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[SO3])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = (Δ[H2O])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sulfur trioxide | barium hydroxide | water | barium sulfate formula | SO_3 | Ba(OH)_2 | H_2O | BaSO_4 Hill formula | O_3S | BaH_2O_2 | H_2O | BaO_4S name | sulfur trioxide | barium hydroxide | water | barium sulfate IUPAC name | sulfur trioxide | barium(+2) cation dihydroxide | water | barium(+2) cation sulfate
| sulfur trioxide | barium hydroxide | water | barium sulfate formula | SO_3 | Ba(OH)_2 | H_2O | BaSO_4 Hill formula | O_3S | BaH_2O_2 | H_2O | BaO_4S name | sulfur trioxide | barium hydroxide | water | barium sulfate IUPAC name | sulfur trioxide | barium(+2) cation dihydroxide | water | barium(+2) cation sulfate

Substance properties

| sulfur trioxide | barium hydroxide | water | barium sulfate molar mass | 80.06 g/mol | 171.34 g/mol | 18.015 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 16.8 °C | 300 °C | 0 °C | 1345 °C boiling point | 44.7 °C | | 99.9839 °C | density | 1.97 g/cm^3 | 2.2 g/cm^3 | 1 g/cm^3 | 4.5 g/cm^3 solubility in water | reacts | | | insoluble surface tension | | | 0.0728 N/m | dynamic viscosity | 0.00159 Pa s (at 30 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| sulfur trioxide | barium hydroxide | water | barium sulfate molar mass | 80.06 g/mol | 171.34 g/mol | 18.015 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 16.8 °C | 300 °C | 0 °C | 1345 °C boiling point | 44.7 °C | | 99.9839 °C | density | 1.97 g/cm^3 | 2.2 g/cm^3 | 1 g/cm^3 | 4.5 g/cm^3 solubility in water | reacts | | | insoluble surface tension | | | 0.0728 N/m | dynamic viscosity | 0.00159 Pa s (at 30 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

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