Input interpretation
fondaparinux sodium | molar mass
Result
Find the molar mass, M, for fondaparinux sodium: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_31H_43N_3Na_10O_49S_8 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 31 H (hydrogen) | 43 N (nitrogen) | 3 Na (sodium) | 10 O (oxygen) | 49 S (sulfur) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 31 | 12.011 H (hydrogen) | 43 | 1.008 N (nitrogen) | 3 | 14.007 Na (sodium) | 10 | 22.98976928 O (oxygen) | 49 | 15.999 S (sulfur) | 8 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 31 | 12.011 | 31 × 12.011 = 372.341 H (hydrogen) | 43 | 1.008 | 43 × 1.008 = 43.344 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 Na (sodium) | 10 | 22.98976928 | 10 × 22.98976928 = 229.89769280 O (oxygen) | 49 | 15.999 | 49 × 15.999 = 783.951 S (sulfur) | 8 | 32.06 | 8 × 32.06 = 256.48 M = 372.341 g/mol + 43.344 g/mol + 42.021 g/mol + 229.89769280 g/mol + 783.951 g/mol + 256.48 g/mol = 1728.03 g/mol
Unit conversion
1.728 kg/mol (kilograms per mole)
Comparisons
≈ 2.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 8.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 30 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.9×10^-21 grams | 2.9×10^-24 kg (kilograms) | 1728 u (unified atomic mass units) | 1.7 kDa (kilodaltons)
Relative molecular mass M_r from M_r = M_u/M: | 1728