Input interpretation
![nitrous acid | orbital hybridization](../image_source/7f53aad46d2e0bd787c3457f2a864a0d.png)
nitrous acid | orbital hybridization
Result
![First draw the structure diagram for nitrous acid, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Assign the provisional hybridization based on the table: Next identify any sp^3 atoms with lone pair electrons which can participate in a conjugated π-bond system. These atoms can lower their energy by placing a lone pair in a unhybridized p orbital to maximize overlap with the neighboring π-bonds. Note that halogens and elements from the third period and below do not engage in bond conjugation, except in the case of aromaticity: Adjust the provisional hybridizations to arrive at the result: Answer: | |](../image_source/c0f08af93556acb25af15b40c0039a53.png)
First draw the structure diagram for nitrous acid, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Assign the provisional hybridization based on the table: Next identify any sp^3 atoms with lone pair electrons which can participate in a conjugated π-bond system. These atoms can lower their energy by placing a lone pair in a unhybridized p orbital to maximize overlap with the neighboring π-bonds. Note that halogens and elements from the third period and below do not engage in bond conjugation, except in the case of aromaticity: Adjust the provisional hybridizations to arrive at the result: Answer: | |
Chemical names and formulas
![formula | HNO_2 name | nitrous acid alternate names | dioxonitric acid | nitrite | nitrosyl hydroxide mass fractions | H (hydrogen) 2.14% | N (nitrogen) 29.8% | O (oxygen) 68.1%](../image_source/5a7956f0ae5d0e6cceec8d82fc1435f0.png)
formula | HNO_2 name | nitrous acid alternate names | dioxonitric acid | nitrite | nitrosyl hydroxide mass fractions | H (hydrogen) 2.14% | N (nitrogen) 29.8% | O (oxygen) 68.1%