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molar mass of nickel(II) sulfamate tetrahydrate

Input interpretation

nickel(II) sulfamate tetrahydrate | molar mass
nickel(II) sulfamate tetrahydrate | molar mass

Result

Find the molar mass, M, for nickel(II) sulfamate tetrahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ni(SO_3NH_2)_2·4H_2O Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  H (hydrogen) | 12  N (nitrogen) | 2  Ni (nickel) | 1  O (oxygen) | 10  S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  H (hydrogen) | 12 | 1.008  N (nitrogen) | 2 | 14.007  Ni (nickel) | 1 | 58.6934  O (oxygen) | 10 | 15.999  S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096  N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014  Ni (nickel) | 1 | 58.6934 | 1 × 58.6934 = 58.6934  O (oxygen) | 10 | 15.999 | 10 × 15.999 = 159.990  S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12  M = 12.096 g/mol + 28.014 g/mol + 58.6934 g/mol + 159.990 g/mol + 64.12 g/mol = 322.91 g/mol
Find the molar mass, M, for nickel(II) sulfamate tetrahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ni(SO_3NH_2)_2·4H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 12 N (nitrogen) | 2 Ni (nickel) | 1 O (oxygen) | 10 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 12 | 1.008 N (nitrogen) | 2 | 14.007 Ni (nickel) | 1 | 58.6934 O (oxygen) | 10 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 Ni (nickel) | 1 | 58.6934 | 1 × 58.6934 = 58.6934 O (oxygen) | 10 | 15.999 | 10 × 15.999 = 159.990 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 12.096 g/mol + 28.014 g/mol + 58.6934 g/mol + 159.990 g/mol + 64.12 g/mol = 322.91 g/mol

Unit conversion

0.32291 kg/mol (kilograms per mole)
0.32291 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 5.4×10^-22 grams  | 5.4×10^-25 kg (kilograms)  | 323 u (unified atomic mass units)  | 323 Da (daltons)
Mass of a molecule m from m = M/N_A: | 5.4×10^-22 grams | 5.4×10^-25 kg (kilograms) | 323 u (unified atomic mass units) | 323 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 323
Relative molecular mass M_r from M_r = M_u/M: | 323