Input interpretation
![2, 4-diethylhepta-2, 6-dienal | molar mass](../image_source/0c15a8067f8c780ad4b6944b43cb9947.png)
2, 4-diethylhepta-2, 6-dienal | molar mass
Result
![Find the molar mass, M, for 2, 4-diethylhepta-2, 6-dienal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCH_2CH(C_2H_5)CH=C(C_2H_5)CHO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 H (hydrogen) | 18 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 H (hydrogen) | 18 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 18 | 1.008 | 18 × 1.008 = 18.144 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 132.121 g/mol + 18.144 g/mol + 15.999 g/mol = 166.264 g/mol](../image_source/73bcf5db8542ca697ca3a41b29275204.png)
Find the molar mass, M, for 2, 4-diethylhepta-2, 6-dienal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCH_2CH(C_2H_5)CH=C(C_2H_5)CHO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 H (hydrogen) | 18 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 H (hydrogen) | 18 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 18 | 1.008 | 18 × 1.008 = 18.144 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 132.121 g/mol + 18.144 g/mol + 15.999 g/mol = 166.264 g/mol
Unit conversion
![0.16626 kg/mol (kilograms per mole)](../image_source/d259b2779edc7e6a0a5e4e3ece050d0d.png)
0.16626 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/eca652c86d82cd081e0fc95950025cb1.png)
≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.86 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/db2745d68dedeb32e90ed87d9c65b604.png)
≈ 0.86 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/def72f8405e6ce2ceef154d2192cc902.png)
≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 166 u (unified atomic mass units) | 166 Da (daltons)](../image_source/3d6bc6ed6f7a9edcbd772e3bb593fb87.png)
Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 166 u (unified atomic mass units) | 166 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 166](../image_source/46c4d7c810b37c19758cac2338e9877f.png)
Relative molecular mass M_r from M_r = M_u/M: | 166