Input interpretation
nitric acid + molybdenum disulfide ⟶ sulfuric acid + nitric oxide + molybdic acid
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Mo and S: H: | c_1 = 2 c_3 + 2 c_5 N: | c_1 = c_4 O: | 3 c_1 = 4 c_3 + c_4 + 4 c_5 Mo: | c_2 = c_5 S: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 2 c_4 = 6 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + ⟶ 2 + 6 +
Structures
+ ⟶ + +
Names
nitric acid + molybdenum disulfide ⟶ sulfuric acid + nitric oxide + molybdic acid
Chemical names and formulas
| nitric acid | molybdenum disulfide | sulfuric acid | nitric oxide | molybdic acid Hill formula | HNO_3 | MoS_2 | H_2O_4S | NO | H_2MoO_4 name | nitric acid | molybdenum disulfide | sulfuric acid | nitric oxide | molybdic acid IUPAC name | nitric acid | dithioxomolybdenum | sulfuric acid | nitric oxide | dihydroxy-dioxo-molybdenum