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K2CO3 + Ba(OH)2 = KOH + BaCO3

Input interpretation

K_2CO_3 pearl ash + Ba(OH)_2 barium hydroxide ⟶ KOH potassium hydroxide + BaCO_3 barium carbonate
K_2CO_3 pearl ash + Ba(OH)_2 barium hydroxide ⟶ KOH potassium hydroxide + BaCO_3 barium carbonate

Balanced equation

Balance the chemical equation algebraically: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2CO_3 + c_2 Ba(OH)_2 ⟶ c_3 KOH + c_4 BaCO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for C, K, O, Ba and H: C: | c_1 = c_4 K: | 2 c_1 = c_3 O: | 3 c_1 + 2 c_2 = c_3 + 3 c_4 Ba: | c_2 = c_4 H: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3
Balance the chemical equation algebraically: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2CO_3 + c_2 Ba(OH)_2 ⟶ c_3 KOH + c_4 BaCO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for C, K, O, Ba and H: C: | c_1 = c_4 K: | 2 c_1 = c_3 O: | 3 c_1 + 2 c_2 = c_3 + 3 c_4 Ba: | c_2 = c_4 H: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3

Structures

 + ⟶ +
+ ⟶ +

Names

pearl ash + barium hydroxide ⟶ potassium hydroxide + barium carbonate
pearl ash + barium hydroxide ⟶ potassium hydroxide + barium carbonate

Reaction thermodynamics

Enthalpy

 | pearl ash | barium hydroxide | potassium hydroxide | barium carbonate molecular enthalpy | -1151 kJ/mol | -944.7 kJ/mol | -424.6 kJ/mol | -1213 kJ/mol total enthalpy | -1151 kJ/mol | -944.7 kJ/mol | -849.2 kJ/mol | -1213 kJ/mol  | H_initial = -2096 kJ/mol | | H_final = -2062 kJ/mol |  ΔH_rxn^0 | -2062 kJ/mol - -2096 kJ/mol = 33.5 kJ/mol (endothermic) | | |
| pearl ash | barium hydroxide | potassium hydroxide | barium carbonate molecular enthalpy | -1151 kJ/mol | -944.7 kJ/mol | -424.6 kJ/mol | -1213 kJ/mol total enthalpy | -1151 kJ/mol | -944.7 kJ/mol | -849.2 kJ/mol | -1213 kJ/mol | H_initial = -2096 kJ/mol | | H_final = -2062 kJ/mol | ΔH_rxn^0 | -2062 kJ/mol - -2096 kJ/mol = 33.5 kJ/mol (endothermic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2CO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 KOH | 2 | 2 BaCO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2CO_3 | 1 | -1 | ([K2CO3])^(-1) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) KOH | 2 | 2 | ([KOH])^2 BaCO_3 | 1 | 1 | [BaCO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([K2CO3])^(-1) ([Ba(OH)2])^(-1) ([KOH])^2 [BaCO3] = (([KOH])^2 [BaCO3])/([K2CO3] [Ba(OH)2])
Construct the equilibrium constant, K, expression for: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2CO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 KOH | 2 | 2 BaCO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2CO_3 | 1 | -1 | ([K2CO3])^(-1) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) KOH | 2 | 2 | ([KOH])^2 BaCO_3 | 1 | 1 | [BaCO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([K2CO3])^(-1) ([Ba(OH)2])^(-1) ([KOH])^2 [BaCO3] = (([KOH])^2 [BaCO3])/([K2CO3] [Ba(OH)2])

Rate of reaction

Construct the rate of reaction expression for: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2CO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 KOH | 2 | 2 BaCO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2CO_3 | 1 | -1 | -(Δ[K2CO3])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) KOH | 2 | 2 | 1/2 (Δ[KOH])/(Δt) BaCO_3 | 1 | 1 | (Δ[BaCO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[K2CO3])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[KOH])/(Δt) = (Δ[BaCO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: K_2CO_3 + Ba(OH)_2 ⟶ KOH + BaCO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2CO_3 + Ba(OH)_2 ⟶ 2 KOH + BaCO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2CO_3 | 1 | -1 Ba(OH)_2 | 1 | -1 KOH | 2 | 2 BaCO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2CO_3 | 1 | -1 | -(Δ[K2CO3])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) KOH | 2 | 2 | 1/2 (Δ[KOH])/(Δt) BaCO_3 | 1 | 1 | (Δ[BaCO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[K2CO3])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[KOH])/(Δt) = (Δ[BaCO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | pearl ash | barium hydroxide | potassium hydroxide | barium carbonate formula | K_2CO_3 | Ba(OH)_2 | KOH | BaCO_3 Hill formula | CK_2O_3 | BaH_2O_2 | HKO | CBaO_3 name | pearl ash | barium hydroxide | potassium hydroxide | barium carbonate IUPAC name | dipotassium carbonate | barium(+2) cation dihydroxide | potassium hydroxide | barium(+2) cation carbonate
| pearl ash | barium hydroxide | potassium hydroxide | barium carbonate formula | K_2CO_3 | Ba(OH)_2 | KOH | BaCO_3 Hill formula | CK_2O_3 | BaH_2O_2 | HKO | CBaO_3 name | pearl ash | barium hydroxide | potassium hydroxide | barium carbonate IUPAC name | dipotassium carbonate | barium(+2) cation dihydroxide | potassium hydroxide | barium(+2) cation carbonate

Substance properties

 | pearl ash | barium hydroxide | potassium hydroxide | barium carbonate molar mass | 138.2 g/mol | 171.34 g/mol | 56.105 g/mol | 197.33 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 891 °C | 300 °C | 406 °C | 1350 °C boiling point | | | 1327 °C |  density | 2.43 g/cm^3 | 2.2 g/cm^3 | 2.044 g/cm^3 | 3.89 g/cm^3 solubility in water | soluble | | soluble | insoluble dynamic viscosity | | | 0.001 Pa s (at 550 °C) |  odor | | | | odorless
| pearl ash | barium hydroxide | potassium hydroxide | barium carbonate molar mass | 138.2 g/mol | 171.34 g/mol | 56.105 g/mol | 197.33 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 891 °C | 300 °C | 406 °C | 1350 °C boiling point | | | 1327 °C | density | 2.43 g/cm^3 | 2.2 g/cm^3 | 2.044 g/cm^3 | 3.89 g/cm^3 solubility in water | soluble | | soluble | insoluble dynamic viscosity | | | 0.001 Pa s (at 550 °C) | odor | | | | odorless

Units