Input interpretation
H_2S hydrogen sulfide + Pb(OH)_2 lead(II) hydroxide ⟶ H_2O water + PbS lead sulfide
Balanced equation
Balance the chemical equation algebraically: H_2S + Pb(OH)_2 ⟶ H_2O + PbS Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2S + c_2 Pb(OH)_2 ⟶ c_3 H_2O + c_4 PbS Set the number of atoms in the reactants equal to the number of atoms in the products for H, S, O and Pb: H: | 2 c_1 + 2 c_2 = 2 c_3 S: | c_1 = c_4 O: | 2 c_2 = c_3 Pb: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2S + Pb(OH)_2 ⟶ 2 H_2O + PbS
Structures
+ ⟶ +
Names
hydrogen sulfide + lead(II) hydroxide ⟶ water + lead sulfide
Equilibrium constant
Construct the equilibrium constant, K, expression for: H_2S + Pb(OH)_2 ⟶ H_2O + PbS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2S + Pb(OH)_2 ⟶ 2 H_2O + PbS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 Pb(OH)_2 | 1 | -1 H_2O | 2 | 2 PbS | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2S | 1 | -1 | ([H2S])^(-1) Pb(OH)_2 | 1 | -1 | ([Pb(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 PbS | 1 | 1 | [PbS] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2S])^(-1) ([Pb(OH)2])^(-1) ([H2O])^2 [PbS] = (([H2O])^2 [PbS])/([H2S] [Pb(OH)2])
Rate of reaction
Construct the rate of reaction expression for: H_2S + Pb(OH)_2 ⟶ H_2O + PbS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2S + Pb(OH)_2 ⟶ 2 H_2O + PbS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 Pb(OH)_2 | 1 | -1 H_2O | 2 | 2 PbS | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2S | 1 | -1 | -(Δ[H2S])/(Δt) Pb(OH)_2 | 1 | -1 | -(Δ[Pb(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) PbS | 1 | 1 | (Δ[PbS])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2S])/(Δt) = -(Δ[Pb(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[PbS])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
| hydrogen sulfide | lead(II) hydroxide | water | lead sulfide formula | H_2S | Pb(OH)_2 | H_2O | PbS Hill formula | H_2S | H_2O_2Pb | H_2O | PbS name | hydrogen sulfide | lead(II) hydroxide | water | lead sulfide IUPAC name | hydrogen sulfide | plumbous dihydroxide | water |
Substance properties
| hydrogen sulfide | lead(II) hydroxide | water | lead sulfide molar mass | 34.08 g/mol | 241.2 g/mol | 18.015 g/mol | 239.3 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -85 °C | | 0 °C | 1114 °C boiling point | -60 °C | | 99.9839 °C | 1344 °C density | 0.001393 g/cm^3 (at 25 °C) | | 1 g/cm^3 | 7.5 g/cm^3 solubility in water | | | | insoluble surface tension | | | 0.0728 N/m | dynamic viscosity | 1.239×10^-5 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
Units