Input interpretation
10-deacetyl-2-debenzoylbaccatin iii | molar mass
Result
Find the molar mass, M, for 10-deacetyl-2-debenzoylbaccatin iii: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_32O_9 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 32 O (oxygen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 22 | 12.011 H (hydrogen) | 32 | 1.008 O (oxygen) | 9 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 32 | 1.008 | 32 × 1.008 = 32.256 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 M = 264.242 g/mol + 32.256 g/mol + 143.991 g/mol = 440.489 g/mol
Unit conversion
0.44049 kg/mol (kilograms per mole)
Comparisons
≈ 0.61 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 7.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 7.3×10^-22 grams | 7.3×10^-25 kg (kilograms) | 440 u (unified atomic mass units) | 440 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 440