Input interpretation
![aluminum hydroxide | molar mass](../image_source/074d8e81ae7947b312f536a81b82f20f.png)
aluminum hydroxide | molar mass
Result
![Find the molar mass, M, for aluminum hydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Al(OH)_3 Use the chemical formula, Al(OH)_3, to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 H (hydrogen) | 3 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 26.9815385 g/mol + 3.024 g/mol + 47.997 g/mol = 78.003 g/mol](../image_source/6596bb42fecf4ad94e0d1003db9e570b.png)
Find the molar mass, M, for aluminum hydroxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Al(OH)_3 Use the chemical formula, Al(OH)_3, to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 H (hydrogen) | 3 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 26.9815385 g/mol + 3.024 g/mol + 47.997 g/mol = 78.003 g/mol
Unit conversion
![0.078003 kg/mol (kilograms per mole)](../image_source/f4fda254a647240a041b9dbf5249f9b1.png)
0.078003 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ca173b8c820aebb1f3cd8932033dd3e4.png)
≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/e6b2c3a1c18586fb3f20a8c5fd8e61f5.png)
≈ 0.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/d7a735493bb3a196efc34c5f9be39bb0.png)
≈ 1.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.3×10^-22 grams | 1.3×10^-25 kg (kilograms) | 78 u (unified atomic mass units) | 78 Da (daltons)](../image_source/8522cbad7f98f4ed3b67de15521f2a25.png)
Mass of a molecule m from m = M/N_A: | 1.3×10^-22 grams | 1.3×10^-25 kg (kilograms) | 78 u (unified atomic mass units) | 78 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 78](../image_source/7565d6f33be6e69210cec3c5866b619d.png)
Relative molecular mass M_r from M_r = M_u/M: | 78