Input interpretation
antimony(III) chloride | molar mass
Result
Find the molar mass, M, for antimony(III) chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: SbCl_3 Use the chemical formula, SbCl_3, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Sb (antimony) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Sb (antimony) | 1 | 121.760 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Sb (antimony) | 1 | 121.760 | 1 × 121.760 = 121.760 M = 106.35 g/mol + 121.760 g/mol = 228.11 g/mol
Unit conversion
0.2281 kg/mol (kilograms per mole)
Comparisons
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 228 u (unified atomic mass units) | 228 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 228