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HCl + I2 + CdS = S + HI + CdCl2

Input interpretation

HCl hydrogen chloride + I_2 iodine + CdS cadmium sulfide ⟶ S mixed sulfur + HI hydrogen iodide + CdCl_2 cadmium chloride
HCl hydrogen chloride + I_2 iodine + CdS cadmium sulfide ⟶ S mixed sulfur + HI hydrogen iodide + CdCl_2 cadmium chloride

Balanced equation

Balance the chemical equation algebraically: HCl + I_2 + CdS ⟶ S + HI + CdCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 I_2 + c_3 CdS ⟶ c_4 S + c_5 HI + c_6 CdCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, I, Cd and S: Cl: | c_1 = 2 c_6 H: | c_1 = c_5 I: | 2 c_2 = c_5 Cd: | c_3 = c_6 S: | c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 HCl + I_2 + CdS ⟶ S + 2 HI + CdCl_2
Balance the chemical equation algebraically: HCl + I_2 + CdS ⟶ S + HI + CdCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 I_2 + c_3 CdS ⟶ c_4 S + c_5 HI + c_6 CdCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, I, Cd and S: Cl: | c_1 = 2 c_6 H: | c_1 = c_5 I: | 2 c_2 = c_5 Cd: | c_3 = c_6 S: | c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HCl + I_2 + CdS ⟶ S + 2 HI + CdCl_2

Structures

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