Input interpretation
![sec-butanol | molar mass](../image_source/dfcd8bc779b48140b9d9f39750a314a5.png)
sec-butanol | molar mass
Result
![Find the molar mass, M, for sec-butanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH_2CH(OH)CH_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 10 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 10 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 48.044 g/mol + 10.080 g/mol + 15.999 g/mol = 74.123 g/mol](../image_source/45db60c4931ec9c80d3bcace65df027e.png)
Find the molar mass, M, for sec-butanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH_2CH(OH)CH_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 10 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 10 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 48.044 g/mol + 10.080 g/mol + 15.999 g/mol = 74.123 g/mol
Unit conversion
![0.07412 kg/mol (kilograms per mole)](../image_source/6d5e05659a21cee06c3719f1f4ce149b.png)
0.07412 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.1 ≈ 1/10 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/3f5450ea569ad0dd4aeb2f0322d6b7b4.png)
≈ ( 0.1 ≈ 1/10 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.38 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/04a67023cf6c06139b9c48b43af7deb2.png)
≈ 0.38 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/0ffd0040ad68c2013eb7209cb0ca9259.png)
≈ 1.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.2×10^-22 grams | 1.2×10^-25 kg (kilograms) | 74 u (unified atomic mass units) | 74 Da (daltons)](../image_source/648aae096f83394fe6f43e2972a39145.png)
Mass of a molecule m from m = M/N_A: | 1.2×10^-22 grams | 1.2×10^-25 kg (kilograms) | 74 u (unified atomic mass units) | 74 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 74](../image_source/169132131ba4c22b82524a6a821797c7.png)
Relative molecular mass M_r from M_r = M_u/M: | 74