Input interpretation
![pentabromobenzyl acrylate | molar mass](../image_source/fb2366661972b7059fdbf5e46730f2c7.png)
pentabromobenzyl acrylate | molar mass
Result
![Find the molar mass, M, for pentabromobenzyl acrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_5Br_5O_2 Use the chemical formula, C_10H_5Br_5O_2, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 5 C (carbon) | 10 H (hydrogen) | 5 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 5 | 79.904 C (carbon) | 10 | 12.011 H (hydrogen) | 5 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 5 | 79.904 | 5 × 79.904 = 399.520 C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 399.520 g/mol + 120.110 g/mol + 5.040 g/mol + 31.998 g/mol = 556.668 g/mol](../image_source/0497314a029c930661dce00377f96e6f.png)
Find the molar mass, M, for pentabromobenzyl acrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_5Br_5O_2 Use the chemical formula, C_10H_5Br_5O_2, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 5 C (carbon) | 10 H (hydrogen) | 5 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 5 | 79.904 C (carbon) | 10 | 12.011 H (hydrogen) | 5 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 5 | 79.904 | 5 × 79.904 = 399.520 C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 399.520 g/mol + 120.110 g/mol + 5.040 g/mol + 31.998 g/mol = 556.668 g/mol
Unit conversion
![0.55667 kg/mol (kilograms per mole)](../image_source/d40efa226ac58006fe8b3313f84d1839.png)
0.55667 kg/mol (kilograms per mole)
Comparisons
![≈ 0.77 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/deaf328e7d6e2fd28cc7bb6a16ae34b2.png)
≈ 0.77 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.9 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/bfd3528985c92d9308750a0406652557.png)
≈ 2.9 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 9.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/9687e1f34627f7f042b1d00db1c0fa01.png)
≈ 9.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 9.2×10^-22 grams | 9.2×10^-25 kg (kilograms) | 557 u (unified atomic mass units) | 557 Da (daltons)](../image_source/d96ffb9cebd8f5d15e32cbeb12c21b18.png)
Mass of a molecule m from m = M/N_A: | 9.2×10^-22 grams | 9.2×10^-25 kg (kilograms) | 557 u (unified atomic mass units) | 557 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 557](../image_source/3ba9e1b2aba9f12563afe0194b95ac90.png)
Relative molecular mass M_r from M_r = M_u/M: | 557