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KOH + MnSO4 + KClO3 = H2O + K2SO4 + KCl + K2MnO4

Input interpretation

potassium hydroxide + manganese(II) sulfate + potassium chlorate ⟶ water + potassium sulfate + potassium chloride + potassium manganate
potassium hydroxide + manganese(II) sulfate + potassium chlorate ⟶ water + potassium sulfate + potassium chloride + potassium manganate

Balanced equation

Balance the chemical equation algebraically:  + + ⟶ + + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7  Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Mn, S and Cl: H: | c_1 = 2 c_4 K: | c_1 + c_3 = 2 c_5 + c_6 + 2 c_7 O: | c_1 + 4 c_2 + 3 c_3 = c_4 + 4 c_5 + 4 c_7 Mn: | c_2 = c_7 S: | c_2 = c_5 Cl: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 3/2 c_3 = 1 c_4 = 3 c_5 = 3/2 c_6 = 1 c_7 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 12 c_2 = 3 c_3 = 2 c_4 = 6 c_5 = 3 c_6 = 2 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 12 + 3 + 2 ⟶ 6 + 3 + 2 + 3
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Mn, S and Cl: H: | c_1 = 2 c_4 K: | c_1 + c_3 = 2 c_5 + c_6 + 2 c_7 O: | c_1 + 4 c_2 + 3 c_3 = c_4 + 4 c_5 + 4 c_7 Mn: | c_2 = c_7 S: | c_2 = c_5 Cl: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 3/2 c_3 = 1 c_4 = 3 c_5 = 3/2 c_6 = 1 c_7 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 12 c_2 = 3 c_3 = 2 c_4 = 6 c_5 = 3 c_6 = 2 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 + 3 + 2 ⟶ 6 + 3 + 2 + 3

Structures

 + + ⟶ + + +
+ + ⟶ + + +

Names

potassium hydroxide + manganese(II) sulfate + potassium chlorate ⟶ water + potassium sulfate + potassium chloride + potassium manganate
potassium hydroxide + manganese(II) sulfate + potassium chlorate ⟶ water + potassium sulfate + potassium chloride + potassium manganate

Chemical names and formulas

 | potassium hydroxide | manganese(II) sulfate | potassium chlorate | water | potassium sulfate | potassium chloride | potassium manganate Hill formula | HKO | MnO_4S | ClKO_3 | H_2O | K_2O_4S | ClK | K_2MnO_4 name | potassium hydroxide | manganese(II) sulfate | potassium chlorate | water | potassium sulfate | potassium chloride | potassium manganate IUPAC name | potassium hydroxide | manganese(+2) cation sulfate | potassium chlorate | water | dipotassium sulfate | potassium chloride | dipotassium dioxido-dioxomanganese
| potassium hydroxide | manganese(II) sulfate | potassium chlorate | water | potassium sulfate | potassium chloride | potassium manganate Hill formula | HKO | MnO_4S | ClKO_3 | H_2O | K_2O_4S | ClK | K_2MnO_4 name | potassium hydroxide | manganese(II) sulfate | potassium chlorate | water | potassium sulfate | potassium chloride | potassium manganate IUPAC name | potassium hydroxide | manganese(+2) cation sulfate | potassium chlorate | water | dipotassium sulfate | potassium chloride | dipotassium dioxido-dioxomanganese