KOH + Br2 + K2SnO2 = H2O + KBr + K2SnO3

potassium hydroxide + bromine + K2SnO2 ⟶ water + potassium bromide + potassium stannate

Balance the chemical equation algebraically: + + K2SnO2 ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 K2SnO2 ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Br and Sn: H: | c_1 = 2 c_4 K: | c_1 + 2 c_3 = c_5 + 2 c_6 O: | c_1 + 2 c_3 = c_4 + 3 c_6 Br: | 2 c_2 = c_5 Sn: | c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + + K2SnO2 ⟶ + 2 +

+ + K2SnO2 ⟶ + +

potassium hydroxide + bromine + K2SnO2 ⟶ water + potassium bromide + potassium stannate

| potassium hydroxide | bromine | K2SnO2 | water | potassium bromide | potassium stannate formula | | | K2SnO2 | | | Hill formula | HKO | Br_2 | K2O2Sn | H_2O | BrK | K_2O_3Sn name | potassium hydroxide | bromine | | water | potassium bromide | potassium stannate IUPAC name | potassium hydroxide | molecular bromine | | water | potassium bromide | dipotassium dioxido-oxo-tin