Input interpretation
sulfuric acid + potassium iodide + sodium nitrite ⟶ water + potassium sulfate + iodine + nitric oxide + sodium sulfate
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 + c_8 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, I, K, N and Na: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 2 c_3 = c_4 + 4 c_5 + c_7 + 4 c_8 S: | c_1 = c_5 + c_8 I: | c_2 = 2 c_6 K: | c_2 = 2 c_5 N: | c_3 = c_7 Na: | c_3 = 2 c_8 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 2 c_4 = 2 c_5 = 1 c_6 = 1 c_7 = 2 c_8 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + 2 + 2 ⟶ 2 + + + 2 +
Structures
+ + ⟶ + + + +
Names
sulfuric acid + potassium iodide + sodium nitrite ⟶ water + potassium sulfate + iodine + nitric oxide + sodium sulfate
Chemical names and formulas
| sulfuric acid | potassium iodide | sodium nitrite | water | potassium sulfate | iodine | nitric oxide | sodium sulfate Hill formula | H_2O_4S | IK | NNaO_2 | H_2O | K_2O_4S | I_2 | NO | Na_2O_4S name | sulfuric acid | potassium iodide | sodium nitrite | water | potassium sulfate | iodine | nitric oxide | sodium sulfate IUPAC name | sulfuric acid | potassium iodide | sodium nitrite | water | dipotassium sulfate | molecular iodine | nitric oxide | disodium sulfate