Input interpretation
activated charcoal + barium sulfate ⟶ carbon monoxide + barium sulfide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for C, Ba, O and S: C: | c_1 = c_3 Ba: | c_2 = c_4 O: | 4 c_2 = c_3 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 4 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + ⟶ 4 +
Structures
+ ⟶ +
Names
activated charcoal + barium sulfate ⟶ carbon monoxide + barium sulfide
Chemical names and formulas
| activated charcoal | barium sulfate | carbon monoxide | barium sulfide Hill formula | C | BaO_4S | CO | BaS name | activated charcoal | barium sulfate | carbon monoxide | barium sulfide IUPAC name | carbon | barium(+2) cation sulfate | carbon monoxide | thioxobarium
Substance properties
| activated charcoal | barium sulfate | carbon monoxide | barium sulfide molar mass | 12.011 g/mol | 233.38 g/mol | 28.01 g/mol | 169.39 g/mol phase | solid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 3550 °C | 1345 °C | -205 °C | 1999.85 °C boiling point | 4027 °C | | -191.5 °C | density | 2.26 g/cm^3 | 4.5 g/cm^3 | 0.001145 g/cm^3 (at 25 °C) | 4.25 g/cm^3 solubility in water | insoluble | insoluble | | dynamic viscosity | | | 1.772×10^-5 Pa s (at 25 °C) | odor | | | odorless |
Units
