Input interpretation
tantalum(V) methoxide | molar mass
Result
Find the molar mass, M, for tantalum(V) methoxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ta(OCH_3)_5 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 5 H (hydrogen) | 15 O (oxygen) | 5 Ta (tantalum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 5 | 12.011 H (hydrogen) | 15 | 1.008 O (oxygen) | 5 | 15.999 Ta (tantalum) | 1 | 180.94788 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 5 | 12.011 | 5 × 12.011 = 60.055 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 Ta (tantalum) | 1 | 180.94788 | 1 × 180.94788 = 180.94788 M = 60.055 g/mol + 15.120 g/mol + 79.995 g/mol + 180.94788 g/mol = 336.118 g/mol
Unit conversion
0.33612 kg/mol (kilograms per mole)
Comparisons
≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 336 u (unified atomic mass units) | 336 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 336