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molar mass of (ethyl benzoate)tricarbonylchromium(0)

Input interpretation

(ethyl benzoate)tricarbonylchromium(0) | molar mass
(ethyl benzoate)tricarbonylchromium(0) | molar mass

Result

Find the molar mass, M, for (ethyl benzoate)tricarbonylchromium(0): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2C_2H_5Cr(CO)_3 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 12  Cr (chromium) | 1  H (hydrogen) | 10  O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 12 | 12.011  Cr (chromium) | 1 | 51.9961  H (hydrogen) | 10 | 1.008  O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132  Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961  H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080  O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995  M = 144.132 g/mol + 51.9961 g/mol + 10.080 g/mol + 79.995 g/mol = 286.203 g/mol
Find the molar mass, M, for (ethyl benzoate)tricarbonylchromium(0): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2C_2H_5Cr(CO)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 Cr (chromium) | 1 H (hydrogen) | 10 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 Cr (chromium) | 1 | 51.9961 H (hydrogen) | 10 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 144.132 g/mol + 51.9961 g/mol + 10.080 g/mol + 79.995 g/mol = 286.203 g/mol

Unit conversion

0.2862 kg/mol (kilograms per mole)
0.2862 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4.8×10^-22 grams  | 4.8×10^-25 kg (kilograms)  | 286 u (unified atomic mass units)  | 286 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 286 u (unified atomic mass units) | 286 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 286
Relative molecular mass M_r from M_r = M_u/M: | 286