Input interpretation
![(ethyl benzoate)tricarbonylchromium(0) | molar mass](../image_source/07cd9cf801ca988dd463059ee1510b60.png)
(ethyl benzoate)tricarbonylchromium(0) | molar mass
Result
![Find the molar mass, M, for (ethyl benzoate)tricarbonylchromium(0): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2C_2H_5Cr(CO)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 Cr (chromium) | 1 H (hydrogen) | 10 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 Cr (chromium) | 1 | 51.9961 H (hydrogen) | 10 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 144.132 g/mol + 51.9961 g/mol + 10.080 g/mol + 79.995 g/mol = 286.203 g/mol](../image_source/a8c086fc32e19aae4a8e7aee09328706.png)
Find the molar mass, M, for (ethyl benzoate)tricarbonylchromium(0): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2C_2H_5Cr(CO)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 Cr (chromium) | 1 H (hydrogen) | 10 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 Cr (chromium) | 1 | 51.9961 H (hydrogen) | 10 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 144.132 g/mol + 51.9961 g/mol + 10.080 g/mol + 79.995 g/mol = 286.203 g/mol
Unit conversion
![0.2862 kg/mol (kilograms per mole)](../image_source/0bb741fa91e21900b5e3f025e9157b78.png)
0.2862 kg/mol (kilograms per mole)
Comparisons
![≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b29483d4985522264ce8c641c9242460.png)
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/0010ad64eff50c8c2b34d958a4035ba2.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/73a725d53de05c7476d8c895d4daaeb9.png)
≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 286 u (unified atomic mass units) | 286 Da (daltons)](../image_source/ad7d4b9bffb8e071f1ec11adaa397906.png)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 286 u (unified atomic mass units) | 286 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 286](../image_source/c9dd17e18dabaebc0065264daf35e6a8.png)
Relative molecular mass M_r from M_r = M_u/M: | 286