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H2O + NaOH + P2O5 = NaH2PO4

Input interpretation

H_2O water + NaOH sodium hydroxide + P2O5 ⟶ NaH_2PO_4 sodium dihydrogen phosphate
H_2O water + NaOH sodium hydroxide + P2O5 ⟶ NaH_2PO_4 sodium dihydrogen phosphate

Balanced equation

Balance the chemical equation algebraically: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 NaOH + c_3 P2O5 ⟶ c_4 NaH_2PO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Na and P: H: | 2 c_1 + c_2 = 2 c_4 O: | c_1 + c_2 + 5 c_3 = 4 c_4 Na: | c_2 = c_4 P: | 2 c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4
Balance the chemical equation algebraically: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 NaOH + c_3 P2O5 ⟶ c_4 NaH_2PO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Na and P: H: | 2 c_1 + c_2 = 2 c_4 O: | c_1 + c_2 + 5 c_3 = 4 c_4 Na: | c_2 = c_4 P: | 2 c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4

Structures

 + + P2O5 ⟶
+ + P2O5 ⟶

Names

water + sodium hydroxide + P2O5 ⟶ sodium dihydrogen phosphate
water + sodium hydroxide + P2O5 ⟶ sodium dihydrogen phosphate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NaOH | 2 | -2 P2O5 | 1 | -1 NaH_2PO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) NaOH | 2 | -2 | ([NaOH])^(-2) P2O5 | 1 | -1 | ([P2O5])^(-1) NaH_2PO_4 | 2 | 2 | ([NaH2PO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2O])^(-1) ([NaOH])^(-2) ([P2O5])^(-1) ([NaH2PO4])^2 = ([NaH2PO4])^2/([H2O] ([NaOH])^2 [P2O5])
Construct the equilibrium constant, K, expression for: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NaOH | 2 | -2 P2O5 | 1 | -1 NaH_2PO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 1 | -1 | ([H2O])^(-1) NaOH | 2 | -2 | ([NaOH])^(-2) P2O5 | 1 | -1 | ([P2O5])^(-1) NaH_2PO_4 | 2 | 2 | ([NaH2PO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-1) ([NaOH])^(-2) ([P2O5])^(-1) ([NaH2PO4])^2 = ([NaH2PO4])^2/([H2O] ([NaOH])^2 [P2O5])

Rate of reaction

Construct the rate of reaction expression for: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NaOH | 2 | -2 P2O5 | 1 | -1 NaH_2PO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) P2O5 | 1 | -1 | -(Δ[P2O5])/(Δt) NaH_2PO_4 | 2 | 2 | 1/2 (Δ[NaH2PO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2O])/(Δt) = -1/2 (Δ[NaOH])/(Δt) = -(Δ[P2O5])/(Δt) = 1/2 (Δ[NaH2PO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + NaOH + P2O5 ⟶ NaH_2PO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O + 2 NaOH + P2O5 ⟶ 2 NaH_2PO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 1 | -1 NaOH | 2 | -2 P2O5 | 1 | -1 NaH_2PO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 1 | -1 | -(Δ[H2O])/(Δt) NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) P2O5 | 1 | -1 | -(Δ[P2O5])/(Δt) NaH_2PO_4 | 2 | 2 | 1/2 (Δ[NaH2PO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O])/(Δt) = -1/2 (Δ[NaOH])/(Δt) = -(Δ[P2O5])/(Δt) = 1/2 (Δ[NaH2PO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | water | sodium hydroxide | P2O5 | sodium dihydrogen phosphate formula | H_2O | NaOH | P2O5 | NaH_2PO_4 Hill formula | H_2O | HNaO | O5P2 | H_2NaO_4P name | water | sodium hydroxide | | sodium dihydrogen phosphate
| water | sodium hydroxide | P2O5 | sodium dihydrogen phosphate formula | H_2O | NaOH | P2O5 | NaH_2PO_4 Hill formula | H_2O | HNaO | O5P2 | H_2NaO_4P name | water | sodium hydroxide | | sodium dihydrogen phosphate

Substance properties

 | water | sodium hydroxide | P2O5 | sodium dihydrogen phosphate molar mass | 18.015 g/mol | 39.997 g/mol | 141.94 g/mol | 119.98 g/mol phase | liquid (at STP) | solid (at STP) | |  melting point | 0 °C | 323 °C | |  boiling point | 99.9839 °C | 1390 °C | |  density | 1 g/cm^3 | 2.13 g/cm^3 | | 0.9996 g/cm^3 solubility in water | | soluble | |  surface tension | 0.0728 N/m | 0.07435 N/m | |  dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | 0.004 Pa s (at 350 °C) | |  odor | odorless | | | odorless
| water | sodium hydroxide | P2O5 | sodium dihydrogen phosphate molar mass | 18.015 g/mol | 39.997 g/mol | 141.94 g/mol | 119.98 g/mol phase | liquid (at STP) | solid (at STP) | | melting point | 0 °C | 323 °C | | boiling point | 99.9839 °C | 1390 °C | | density | 1 g/cm^3 | 2.13 g/cm^3 | | 0.9996 g/cm^3 solubility in water | | soluble | | surface tension | 0.0728 N/m | 0.07435 N/m | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | 0.004 Pa s (at 350 °C) | | odor | odorless | | | odorless

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