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molar mass of cadmium dichromate monohydrate

Input interpretation

cadmium dichromate monohydrate | molar mass
cadmium dichromate monohydrate | molar mass

Result

Find the molar mass, M, for cadmium dichromate monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdCr_2O_7·H_2O Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Cd (cadmium) | 1  Cr (chromium) | 2  H (hydrogen) | 2  O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Cd (cadmium) | 1 | 112.414  Cr (chromium) | 2 | 51.9961  H (hydrogen) | 2 | 1.008  O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414  Cr (chromium) | 2 | 51.9961 | 2 × 51.9961 = 103.9922  H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016  O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992  M = 112.414 g/mol + 103.9922 g/mol + 2.016 g/mol + 127.992 g/mol = 346.414 g/mol
Find the molar mass, M, for cadmium dichromate monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdCr_2O_7·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 1 Cr (chromium) | 2 H (hydrogen) | 2 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 1 | 112.414 Cr (chromium) | 2 | 51.9961 H (hydrogen) | 2 | 1.008 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 Cr (chromium) | 2 | 51.9961 | 2 × 51.9961 = 103.9922 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 112.414 g/mol + 103.9922 g/mol + 2.016 g/mol + 127.992 g/mol = 346.414 g/mol

Unit conversion

0.34641 kg/mol (kilograms per mole)
0.34641 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 5.8×10^-22 grams  | 5.8×10^-25 kg (kilograms)  | 346 u (unified atomic mass units)  | 346 Da (daltons)
Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 346 u (unified atomic mass units) | 346 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 346
Relative molecular mass M_r from M_r = M_u/M: | 346