Input interpretation
![cadmium dichromate monohydrate | molar mass](../image_source/fe6e9be1163e1dbfc8d8e27f7410315f.png)
cadmium dichromate monohydrate | molar mass
Result
![Find the molar mass, M, for cadmium dichromate monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdCr_2O_7·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 1 Cr (chromium) | 2 H (hydrogen) | 2 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 1 | 112.414 Cr (chromium) | 2 | 51.9961 H (hydrogen) | 2 | 1.008 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 Cr (chromium) | 2 | 51.9961 | 2 × 51.9961 = 103.9922 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 112.414 g/mol + 103.9922 g/mol + 2.016 g/mol + 127.992 g/mol = 346.414 g/mol](../image_source/b8d58f7e5f0aa4095ddf7fdbf396561a.png)
Find the molar mass, M, for cadmium dichromate monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdCr_2O_7·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 1 Cr (chromium) | 2 H (hydrogen) | 2 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 1 | 112.414 Cr (chromium) | 2 | 51.9961 H (hydrogen) | 2 | 1.008 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 Cr (chromium) | 2 | 51.9961 | 2 × 51.9961 = 103.9922 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 112.414 g/mol + 103.9922 g/mol + 2.016 g/mol + 127.992 g/mol = 346.414 g/mol
Unit conversion
![0.34641 kg/mol (kilograms per mole)](../image_source/3ee0dfe716f5474453d90add592e0b9e.png)
0.34641 kg/mol (kilograms per mole)
Comparisons
![≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/15893549b76cb2179e9e3b0590a56f09.png)
≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/e323f1e9475eba3af1e4bfbed499465f.png)
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/f2228d8df4f88cea0e6d44b0b07ea381.png)
≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 346 u (unified atomic mass units) | 346 Da (daltons)](../image_source/1f2fd3dab7ea1856d3b38d382f74f059.png)
Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 346 u (unified atomic mass units) | 346 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 346](../image_source/3018abaf8cd76edc5146db5d6dca99d1.png)
Relative molecular mass M_r from M_r = M_u/M: | 346