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molar mass of 2,5-bis(trifluoromethyl)benzyl alcohol

Input interpretation

2, 5-bis(trifluoromethyl)benzyl alcohol | molar mass
2, 5-bis(trifluoromethyl)benzyl alcohol | molar mass

Result

Find the molar mass, M, for 2, 5-bis(trifluoromethyl)benzyl alcohol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CF_3)_2C_6H_3CH_2OH Use the chemical formula, (CF_3)_2C_6H_3CH_2OH, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 9  F (fluorine) | 6  H (hydrogen) | 6  O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 9 | 12.011  F (fluorine) | 6 | 18.998403163  H (hydrogen) | 6 | 1.008  O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099  F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978  H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048  O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999  M = 108.099 g/mol + 113.990418978 g/mol + 6.048 g/mol + 15.999 g/mol = 244.136 g/mol
Find the molar mass, M, for 2, 5-bis(trifluoromethyl)benzyl alcohol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CF_3)_2C_6H_3CH_2OH Use the chemical formula, (CF_3)_2C_6H_3CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 F (fluorine) | 6 H (hydrogen) | 6 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 6 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 113.990418978 g/mol + 6.048 g/mol + 15.999 g/mol = 244.136 g/mol

Unit conversion

0.24414 kg/mol (kilograms per mole)
0.24414 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 4.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 4.2 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4.1×10^-22 grams  | 4.1×10^-25 kg (kilograms)  | 244 u (unified atomic mass units)  | 244 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4.1×10^-22 grams | 4.1×10^-25 kg (kilograms) | 244 u (unified atomic mass units) | 244 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 244
Relative molecular mass M_r from M_r = M_u/M: | 244