Input interpretation
![(1, 3-dioxolan-2-ylmethyl)magnesium bromide | molar mass](../image_source/21499d57810b2f1f473f6d3ceb7aa068.png)
(1, 3-dioxolan-2-ylmethyl)magnesium bromide | molar mass
Result
![Find the molar mass, M, for (1, 3-dioxolan-2-ylmethyl)magnesium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_4H_7BrMgO_2 Use the chemical formula, C_4H_7BrMgO_2, to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 2 C (carbon) | 4 Mg (magnesium) | 1 Br (bromine) | 1 H (hydrogen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 2 | 15.999 C (carbon) | 4 | 12.011 Mg (magnesium) | 1 | 24.305 Br (bromine) | 1 | 79.904 H (hydrogen) | 7 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 M = 31.998 g/mol + 48.044 g/mol + 24.305 g/mol + 79.904 g/mol + 7.056 g/mol = 191.307 g/mol](../image_source/fe15b5d24672b8ee5b0cad0a74755bca.png)
Find the molar mass, M, for (1, 3-dioxolan-2-ylmethyl)magnesium bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_4H_7BrMgO_2 Use the chemical formula, C_4H_7BrMgO_2, to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 2 C (carbon) | 4 Mg (magnesium) | 1 Br (bromine) | 1 H (hydrogen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 2 | 15.999 C (carbon) | 4 | 12.011 Mg (magnesium) | 1 | 24.305 Br (bromine) | 1 | 79.904 H (hydrogen) | 7 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 Mg (magnesium) | 1 | 24.305 | 1 × 24.305 = 24.305 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 M = 31.998 g/mol + 48.044 g/mol + 24.305 g/mol + 79.904 g/mol + 7.056 g/mol = 191.307 g/mol
Unit conversion
![0.1913 kg/mol (kilograms per mole)](../image_source/8db3b0f89b783cbcbf77d3040cd341a5.png)
0.1913 kg/mol (kilograms per mole)
Comparisons
![≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b9b2c311f0703da3abff353555e97dcb.png)
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.99 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/c934f5d3a794cb795369c553e927cec7.png)
≈ 0.99 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/07be1d49b188823a2abad220d1ae7b92.png)
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)](../image_source/8c64a498f928556858ffbb254ffca788.png)
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 191](../image_source/57d3f3932a2a60bd4a8cf1ef94a4ebdf.png)
Relative molecular mass M_r from M_r = M_u/M: | 191