hybridization of iodine azide

iodine azide | orbital hybridization

First draw the structure diagram for iodine azide, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Now assign the hybridization for each atom: Answer: | |

formula | IN_3 name | iodine azide alternate names | iodine(I) azide | iodoazide mass fractions | I (iodine) 75.1% | N (nitrogen) 24.9%

I^- (iodide anion) | 1 (N_3)^- (azide anion) | 1