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HNO3 + Si + HF = H2O + NO + H2SiF6

Input interpretation

nitric acid + silicon + hydrogen fluoride ⟶ water + nitric oxide + fluorosilicic acid
nitric acid + silicon + hydrogen fluoride ⟶ water + nitric oxide + fluorosilicic acid

Balanced equation

Balance the chemical equation algebraically:  + + ⟶ + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6  Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Si and F: H: | c_1 + c_3 = 2 c_4 + 2 c_6 N: | c_1 = c_5 O: | 3 c_1 = c_4 + c_5 Si: | c_2 = c_6 F: | c_3 = 6 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4/3 c_2 = 1 c_3 = 6 c_4 = 8/3 c_5 = 4/3 c_6 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 4 c_2 = 3 c_3 = 18 c_4 = 8 c_5 = 4 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 4 + 3 + 18 ⟶ 8 + 4 + 3
Balance the chemical equation algebraically: + + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Si and F: H: | c_1 + c_3 = 2 c_4 + 2 c_6 N: | c_1 = c_5 O: | 3 c_1 = c_4 + c_5 Si: | c_2 = c_6 F: | c_3 = 6 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4/3 c_2 = 1 c_3 = 6 c_4 = 8/3 c_5 = 4/3 c_6 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 4 c_2 = 3 c_3 = 18 c_4 = 8 c_5 = 4 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 3 + 18 ⟶ 8 + 4 + 3

Structures

 + + ⟶ + +
+ + ⟶ + +

Names

nitric acid + silicon + hydrogen fluoride ⟶ water + nitric oxide + fluorosilicic acid
nitric acid + silicon + hydrogen fluoride ⟶ water + nitric oxide + fluorosilicic acid

Chemical names and formulas

 | nitric acid | silicon | hydrogen fluoride | water | nitric oxide | fluorosilicic acid Hill formula | HNO_3 | Si | FH | H_2O | NO | F_6H_2Si name | nitric acid | silicon | hydrogen fluoride | water | nitric oxide | fluorosilicic acid IUPAC name | nitric acid | silicon | hydrogen fluoride | water | nitric oxide | tetrafluorosilane dihydrofluoride
| nitric acid | silicon | hydrogen fluoride | water | nitric oxide | fluorosilicic acid Hill formula | HNO_3 | Si | FH | H_2O | NO | F_6H_2Si name | nitric acid | silicon | hydrogen fluoride | water | nitric oxide | fluorosilicic acid IUPAC name | nitric acid | silicon | hydrogen fluoride | water | nitric oxide | tetrafluorosilane dihydrofluoride