Input interpretation
![yttrium(III) orthovanadate | molar mass](../image_source/87fb31aecd9017e7efd99eac35e1f164.png)
yttrium(III) orthovanadate | molar mass
Result
![Find the molar mass, M, for yttrium(III) orthovanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YVO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 4 V (vanadium) | 1 Y (yttrium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 4 | 15.999 V (vanadium) | 1 | 50.9415 Y (yttrium) | 1 | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 Y (yttrium) | 1 | 88.90584 | 1 × 88.90584 = 88.90584 M = 63.996 g/mol + 50.9415 g/mol + 88.90584 g/mol = 203.843 g/mol](../image_source/3c33afd5254c892838831343a5843c7c.png)
Find the molar mass, M, for yttrium(III) orthovanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YVO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 4 V (vanadium) | 1 Y (yttrium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 4 | 15.999 V (vanadium) | 1 | 50.9415 Y (yttrium) | 1 | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 Y (yttrium) | 1 | 88.90584 | 1 × 88.90584 = 88.90584 M = 63.996 g/mol + 50.9415 g/mol + 88.90584 g/mol = 203.843 g/mol
Unit conversion
![0.20384 kg/mol (kilograms per mole)](../image_source/5e960f533b9d1780c279fea4e0ba3d22.png)
0.20384 kg/mol (kilograms per mole)
Comparisons
![≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/74df18fc2906600502195683b700bad4.png)
≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ molar mass of caffeine ( ≈ 194 g/mol )](../image_source/511b1c006cbb665819c704eacc97fa2a.png)
≈ molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/acd9593f403fd67cd0e4b9dada7bfa5d.png)
≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.4×10^-22 grams | 3.4×10^-25 kg (kilograms) | 204 u (unified atomic mass units) | 204 Da (daltons)](../image_source/4836283280bbd6321a54bb1ec711e0c1.png)
Mass of a molecule m from m = M/N_A: | 3.4×10^-22 grams | 3.4×10^-25 kg (kilograms) | 204 u (unified atomic mass units) | 204 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 204](../image_source/0843b8750d12c6e5a877f7ce20cf8bcd.png)
Relative molecular mass M_r from M_r = M_u/M: | 204