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molar mass of yttrium(III) orthovanadate

Input interpretation

yttrium(III) orthovanadate | molar mass
yttrium(III) orthovanadate | molar mass

Result

Find the molar mass, M, for yttrium(III) orthovanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YVO_4 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  O (oxygen) | 4  V (vanadium) | 1  Y (yttrium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  O (oxygen) | 4 | 15.999  V (vanadium) | 1 | 50.9415  Y (yttrium) | 1 | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996  V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415  Y (yttrium) | 1 | 88.90584 | 1 × 88.90584 = 88.90584  M = 63.996 g/mol + 50.9415 g/mol + 88.90584 g/mol = 203.843 g/mol
Find the molar mass, M, for yttrium(III) orthovanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: YVO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i O (oxygen) | 4 V (vanadium) | 1 Y (yttrium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) O (oxygen) | 4 | 15.999 V (vanadium) | 1 | 50.9415 Y (yttrium) | 1 | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 Y (yttrium) | 1 | 88.90584 | 1 × 88.90584 = 88.90584 M = 63.996 g/mol + 50.9415 g/mol + 88.90584 g/mol = 203.843 g/mol

Unit conversion

0.20384 kg/mol (kilograms per mole)
0.20384 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ molar mass of caffeine ( ≈ 194 g/mol )
≈ molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.4×10^-22 grams  | 3.4×10^-25 kg (kilograms)  | 204 u (unified atomic mass units)  | 204 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.4×10^-22 grams | 3.4×10^-25 kg (kilograms) | 204 u (unified atomic mass units) | 204 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 204
Relative molecular mass M_r from M_r = M_u/M: | 204