Input interpretation
![O_2 oxygen + C2H10 ⟶ H_2O water + CO_2 carbon dioxide](../image_source/d1ec58e64051f287a43bff2ce5ff8832.png)
O_2 oxygen + C2H10 ⟶ H_2O water + CO_2 carbon dioxide
Balanced equation
![Balance the chemical equation algebraically: O_2 + C2H10 ⟶ H_2O + CO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C2H10 ⟶ c_3 H_2O + c_4 CO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 C: | 2 c_2 = c_4 H: | 10 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 5 c_4 = 2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 10 c_4 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2](../image_source/fac8453497f42faab2d8125e304d860e.png)
Balance the chemical equation algebraically: O_2 + C2H10 ⟶ H_2O + CO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C2H10 ⟶ c_3 H_2O + c_4 CO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 C: | 2 c_2 = c_4 H: | 10 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 5 c_4 = 2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 10 c_4 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2
Structures
![+ C2H10 ⟶ +](../image_source/99d0f05ef3522a5df843f6a517b5fde9.png)
+ C2H10 ⟶ +
Names
![oxygen + C2H10 ⟶ water + carbon dioxide](../image_source/00e62283ba417885e0b8bc571caac508.png)
oxygen + C2H10 ⟶ water + carbon dioxide
Equilibrium constant
![Construct the equilibrium constant, K, expression for: O_2 + C2H10 ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 9 | -9 C2H10 | 2 | -2 H_2O | 10 | 10 CO_2 | 4 | 4 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 9 | -9 | ([O2])^(-9) C2H10 | 2 | -2 | ([C2H10])^(-2) H_2O | 10 | 10 | ([H2O])^10 CO_2 | 4 | 4 | ([CO2])^4 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-9) ([C2H10])^(-2) ([H2O])^10 ([CO2])^4 = (([H2O])^10 ([CO2])^4)/(([O2])^9 ([C2H10])^2)](../image_source/0cf798ee760dfdc5f05b79bb9ac58491.png)
Construct the equilibrium constant, K, expression for: O_2 + C2H10 ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 9 | -9 C2H10 | 2 | -2 H_2O | 10 | 10 CO_2 | 4 | 4 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 9 | -9 | ([O2])^(-9) C2H10 | 2 | -2 | ([C2H10])^(-2) H_2O | 10 | 10 | ([H2O])^10 CO_2 | 4 | 4 | ([CO2])^4 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-9) ([C2H10])^(-2) ([H2O])^10 ([CO2])^4 = (([H2O])^10 ([CO2])^4)/(([O2])^9 ([C2H10])^2)
Rate of reaction
![Construct the rate of reaction expression for: O_2 + C2H10 ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 9 | -9 C2H10 | 2 | -2 H_2O | 10 | 10 CO_2 | 4 | 4 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 9 | -9 | -1/9 (Δ[O2])/(Δt) C2H10 | 2 | -2 | -1/2 (Δ[C2H10])/(Δt) H_2O | 10 | 10 | 1/10 (Δ[H2O])/(Δt) CO_2 | 4 | 4 | 1/4 (Δ[CO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/9 (Δ[O2])/(Δt) = -1/2 (Δ[C2H10])/(Δt) = 1/10 (Δ[H2O])/(Δt) = 1/4 (Δ[CO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/8dcdb803afa636aacdb604d42c4a085c.png)
Construct the rate of reaction expression for: O_2 + C2H10 ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 9 O_2 + 2 C2H10 ⟶ 10 H_2O + 4 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 9 | -9 C2H10 | 2 | -2 H_2O | 10 | 10 CO_2 | 4 | 4 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 9 | -9 | -1/9 (Δ[O2])/(Δt) C2H10 | 2 | -2 | -1/2 (Δ[C2H10])/(Δt) H_2O | 10 | 10 | 1/10 (Δ[H2O])/(Δt) CO_2 | 4 | 4 | 1/4 (Δ[CO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/9 (Δ[O2])/(Δt) = -1/2 (Δ[C2H10])/(Δt) = 1/10 (Δ[H2O])/(Δt) = 1/4 (Δ[CO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| oxygen | C2H10 | water | carbon dioxide formula | O_2 | C2H10 | H_2O | CO_2 name | oxygen | | water | carbon dioxide IUPAC name | molecular oxygen | | water | carbon dioxide](../image_source/eb45c823e7fa53dc15aeacc195aaa05f.png)
| oxygen | C2H10 | water | carbon dioxide formula | O_2 | C2H10 | H_2O | CO_2 name | oxygen | | water | carbon dioxide IUPAC name | molecular oxygen | | water | carbon dioxide
Substance properties
![| oxygen | C2H10 | water | carbon dioxide molar mass | 31.998 g/mol | 34.1 g/mol | 18.015 g/mol | 44.009 g/mol phase | gas (at STP) | | liquid (at STP) | gas (at STP) melting point | -218 °C | | 0 °C | -56.56 °C (at triple point) boiling point | -183 °C | | 99.9839 °C | -78.5 °C (at sublimation point) density | 0.001429 g/cm^3 (at 0 °C) | | 1 g/cm^3 | 0.00184212 g/cm^3 (at 20 °C) surface tension | 0.01347 N/m | | 0.0728 N/m | dynamic viscosity | 2.055×10^-5 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | 1.491×10^-5 Pa s (at 25 °C) odor | odorless | | odorless | odorless](../image_source/05645ceb82e2ba925eb4403f39d0113b.png)
| oxygen | C2H10 | water | carbon dioxide molar mass | 31.998 g/mol | 34.1 g/mol | 18.015 g/mol | 44.009 g/mol phase | gas (at STP) | | liquid (at STP) | gas (at STP) melting point | -218 °C | | 0 °C | -56.56 °C (at triple point) boiling point | -183 °C | | 99.9839 °C | -78.5 °C (at sublimation point) density | 0.001429 g/cm^3 (at 0 °C) | | 1 g/cm^3 | 0.00184212 g/cm^3 (at 20 °C) surface tension | 0.01347 N/m | | 0.0728 N/m | dynamic viscosity | 2.055×10^-5 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | 1.491×10^-5 Pa s (at 25 °C) odor | odorless | | odorless | odorless
Units