Input interpretation
![1, 1, 1-trifluoro-2-phenyl-3-butyn-2-ol | molar mass](../image_source/360b623370ae75cc27404b43c50a052c.png)
1, 1, 1-trifluoro-2-phenyl-3-butyn-2-ol | molar mass
Result
![Find the molar mass, M, for 1, 1, 1-trifluoro-2-phenyl-3-butyn-2-ol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CHC(C_6H_5)(OH)CF_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 F (fluorine) | 3 H (hydrogen) | 7 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 7 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 120.110 g/mol + 56.995209489 g/mol + 7.056 g/mol + 15.999 g/mol = 200.160 g/mol](../image_source/2f218a282a251b07d5a73119b9e18b17.png)
Find the molar mass, M, for 1, 1, 1-trifluoro-2-phenyl-3-butyn-2-ol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CHC(C_6H_5)(OH)CF_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 F (fluorine) | 3 H (hydrogen) | 7 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 7 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 120.110 g/mol + 56.995209489 g/mol + 7.056 g/mol + 15.999 g/mol = 200.160 g/mol
Unit conversion
![0.20016 kg/mol (kilograms per mole)](../image_source/c850506294947f34a13a1a2299677608.png)
0.20016 kg/mol (kilograms per mole)
Comparisons
![≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/d1f4a26e2a3f4859295f371d429532ab.png)
≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ molar mass of caffeine ( ≈ 194 g/mol )](../image_source/9632c72fa79709cd74e7cfea1ff19edc.png)
≈ molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/fdb4d315d1f4d1828dc44650d76b49ad.png)
≈ 3.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.3×10^-22 grams | 3.3×10^-25 kg (kilograms) | 200 u (unified atomic mass units) | 200 Da (daltons)](../image_source/331720cc6a80cee0e09a0b30cdc63ac1.png)
Mass of a molecule m from m = M/N_A: | 3.3×10^-22 grams | 3.3×10^-25 kg (kilograms) | 200 u (unified atomic mass units) | 200 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 200](../image_source/d3ab3295a730286d118b97c3f0391ffa.png)
Relative molecular mass M_r from M_r = M_u/M: | 200