Input interpretation
![iron(III) pyrophosphate nonahydrate | molar mass](../image_source/3d159a0776bda7453f3e6e06cf4a79bb.png)
iron(III) pyrophosphate nonahydrate | molar mass
Result
![Find the molar mass, M, for iron(III) pyrophosphate nonahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Fe_4(P_2O_7)_3·9H_2O Use the chemical formula, Fe_4(P_2O_7)_3·9H_2O, to count the number of atoms, N_i, for each element: | N_i Fe (iron) | 4 O (oxygen) | 21 P (phosphorus) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Fe (iron) | 4 | 55.845 O (oxygen) | 21 | 15.999 P (phosphorus) | 6 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Fe (iron) | 4 | 55.845 | 4 × 55.845 = 223.380 O (oxygen) | 21 | 15.999 | 21 × 15.999 = 335.979 P (phosphorus) | 6 | 30.973761998 | 6 × 30.973761998 = 185.842571988 M = 223.380 g/mol + 335.979 g/mol + 185.842571988 g/mol = 745.202 g/mol](../image_source/27f37f3829bd5713ca2d40e74b905e3c.png)
Find the molar mass, M, for iron(III) pyrophosphate nonahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Fe_4(P_2O_7)_3·9H_2O Use the chemical formula, Fe_4(P_2O_7)_3·9H_2O, to count the number of atoms, N_i, for each element: | N_i Fe (iron) | 4 O (oxygen) | 21 P (phosphorus) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Fe (iron) | 4 | 55.845 O (oxygen) | 21 | 15.999 P (phosphorus) | 6 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Fe (iron) | 4 | 55.845 | 4 × 55.845 = 223.380 O (oxygen) | 21 | 15.999 | 21 × 15.999 = 335.979 P (phosphorus) | 6 | 30.973761998 | 6 × 30.973761998 = 185.842571988 M = 223.380 g/mol + 335.979 g/mol + 185.842571988 g/mol = 745.202 g/mol
Unit conversion
![0.7452 kg/mol (kilograms per mole)](../image_source/23451600f6bfacc769f014f876528919.png)
0.7452 kg/mol (kilograms per mole)
Comparisons
![≈ molar mass of fullerene ( ≈ 721 g/mol )](../image_source/103a5d397cb5c6626b7925d35d2ec963.png)
≈ molar mass of fullerene ( ≈ 721 g/mol )
![≈ 3.8 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/497aeb725d45b91668a14d9cabfe3eeb.png)
≈ 3.8 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 13 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/773525751d19c0ef304400a849e7671b.png)
≈ 13 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.2×10^-21 grams | 1.2×10^-24 kg (kilograms) | 745 u (unified atomic mass units) | 745 Da (daltons)](../image_source/d8789fa7994b1d4b4fa1393b9495ab44.png)
Mass of a molecule m from m = M/N_A: | 1.2×10^-21 grams | 1.2×10^-24 kg (kilograms) | 745 u (unified atomic mass units) | 745 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 745](../image_source/04a221b71392fbd71c517cd3932fa39e.png)
Relative molecular mass M_r from M_r = M_u/M: | 745