Input interpretation
![cytembena | molar mass](../image_source/4ee9c0f2521fa8d6a7e0180c59ba9835.png)
cytembena | molar mass
Result
![Find the molar mass, M, for cytembena: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_8BrO_4Na Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 11 H (hydrogen) | 8 Na (sodium) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 11 | 12.011 H (hydrogen) | 8 | 1.008 Na (sodium) | 1 | 22.98976928 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 79.904 g/mol + 132.121 g/mol + 8.064 g/mol + 22.98976928 g/mol + 63.996 g/mol = 307.075 g/mol](../image_source/beedd6744b7d998ee3609fddd7e5ce78.png)
Find the molar mass, M, for cytembena: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_8BrO_4Na Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 11 H (hydrogen) | 8 Na (sodium) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 11 | 12.011 H (hydrogen) | 8 | 1.008 Na (sodium) | 1 | 22.98976928 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 79.904 g/mol + 132.121 g/mol + 8.064 g/mol + 22.98976928 g/mol + 63.996 g/mol = 307.075 g/mol
Unit conversion
![0.30707 kg/mol (kilograms per mole)](../image_source/bd98a07bb617ef5d13cafd821c0b0e57.png)
0.30707 kg/mol (kilograms per mole)
Comparisons
![≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/7751dcb8cf10324a2e8a6fb022563ab2.png)
≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/c0a7a1c1d304fc6c910d92b83a6c4d1b.png)
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/2be32d27c6f1c9d209e5d8c33babb218.png)
≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 307 u (unified atomic mass units) | 307 Da (daltons)](../image_source/0c221b477e718d83cf963dcc57abb5f5.png)
Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 307 u (unified atomic mass units) | 307 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 307](../image_source/70e0459e0e371bc020faf3a2ca7293a7.png)
Relative molecular mass M_r from M_r = M_u/M: | 307