Input interpretation
boron tribromide dimethyl sulfide complex | molar mass
Result
Find the molar mass, M, for boron tribromide dimethyl sulfide complex: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BBr_3·S(CH_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Br (bromine) | 3 C (carbon) | 2 H (hydrogen) | 6 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Br (bromine) | 3 | 79.904 C (carbon) | 2 | 12.011 H (hydrogen) | 6 | 1.008 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Br (bromine) | 3 | 79.904 | 3 × 79.904 = 239.712 C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 10.81 g/mol + 239.712 g/mol + 24.022 g/mol + 6.048 g/mol + 32.06 g/mol = 312.65 g/mol
Unit conversion
0.31265 kg/mol (kilograms per mole)
Comparisons
≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.2×10^-22 grams | 5.2×10^-25 kg (kilograms) | 313 u (unified atomic mass units) | 313 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 313