Search

HF + Sc(OH)3 = H2O + ScF3

Input interpretation

HF hydrogen fluoride + Sc(OH)_3 scandium hydroxide ⟶ H_2O water + ScF_3 scandium fluoride
HF hydrogen fluoride + Sc(OH)_3 scandium hydroxide ⟶ H_2O water + ScF_3 scandium fluoride

Balanced equation

Balance the chemical equation algebraically: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HF + c_2 Sc(OH)_3 ⟶ c_3 H_2O + c_4 ScF_3 Set the number of atoms in the reactants equal to the number of atoms in the products for F, H, O and Sc: F: | c_1 = 3 c_4 H: | c_1 + 3 c_2 = 2 c_3 O: | 3 c_2 = c_3 Sc: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3
Balance the chemical equation algebraically: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HF + c_2 Sc(OH)_3 ⟶ c_3 H_2O + c_4 ScF_3 Set the number of atoms in the reactants equal to the number of atoms in the products for F, H, O and Sc: F: | c_1 = 3 c_4 H: | c_1 + 3 c_2 = 2 c_3 O: | 3 c_2 = c_3 Sc: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3

Structures

+ ⟶ +
+ ⟶ +

Names

hydrogen fluoride + scandium hydroxide ⟶ water + scandium fluoride
hydrogen fluoride + scandium hydroxide ⟶ water + scandium fluoride

Equilibrium constant

Construct the equilibrium constant, K, expression for: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HF | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScF_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HF | 3 | -3 | ([HF])^(-3) Sc(OH)_3 | 1 | -1 | ([Sc(OH)3])^(-1) H_2O | 3 | 3 | ([H2O])^3 ScF_3 | 1 | 1 | [ScF3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HF])^(-3) ([Sc(OH)3])^(-1) ([H2O])^3 [ScF3] = (([H2O])^3 [ScF3])/(([HF])^3 [Sc(OH)3])
Construct the equilibrium constant, K, expression for: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HF | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScF_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HF | 3 | -3 | ([HF])^(-3) Sc(OH)_3 | 1 | -1 | ([Sc(OH)3])^(-1) H_2O | 3 | 3 | ([H2O])^3 ScF_3 | 1 | 1 | [ScF3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HF])^(-3) ([Sc(OH)3])^(-1) ([H2O])^3 [ScF3] = (([H2O])^3 [ScF3])/(([HF])^3 [Sc(OH)3])

Rate of reaction

Construct the rate of reaction expression for: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HF | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScF_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HF | 3 | -3 | -1/3 (Δ[HF])/(Δt) Sc(OH)_3 | 1 | -1 | -(Δ[Sc(OH)3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) ScF_3 | 1 | 1 | (Δ[ScF3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[HF])/(Δt) = -(Δ[Sc(OH)3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = (Δ[ScF3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HF + Sc(OH)_3 ⟶ H_2O + ScF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 HF + Sc(OH)_3 ⟶ 3 H_2O + ScF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HF | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScF_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HF | 3 | -3 | -1/3 (Δ[HF])/(Δt) Sc(OH)_3 | 1 | -1 | -(Δ[Sc(OH)3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) ScF_3 | 1 | 1 | (Δ[ScF3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[HF])/(Δt) = -(Δ[Sc(OH)3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = (Δ[ScF3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| hydrogen fluoride | scandium hydroxide | water | scandium fluoride formula | HF | Sc(OH)_3 | H_2O | ScF_3 Hill formula | FH | H_3O_3Sc | H_2O | F_3Sc name | hydrogen fluoride | scandium hydroxide | water | scandium fluoride IUPAC name | hydrogen fluoride | scandium(+3) cation trihydroxide | water |
| hydrogen fluoride | scandium hydroxide | water | scandium fluoride formula | HF | Sc(OH)_3 | H_2O | ScF_3 Hill formula | FH | H_3O_3Sc | H_2O | F_3Sc name | hydrogen fluoride | scandium hydroxide | water | scandium fluoride IUPAC name | hydrogen fluoride | scandium(+3) cation trihydroxide | water |

Substance properties

| hydrogen fluoride | scandium hydroxide | water | scandium fluoride molar mass | 20.006 g/mol | 95.977 g/mol | 18.015 g/mol | 101.95112 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -83.36 °C | | 0 °C | 1150 °C boiling point | 19.5 °C | | 99.9839 °C | 1527 °C density | 8.18×10^-4 g/cm^3 (at 25 °C) | | 1 g/cm^3 | 2.52 g/cm^3 solubility in water | miscible | | | surface tension | | | 0.0728 N/m | dynamic viscosity | 1.2571×10^-5 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| hydrogen fluoride | scandium hydroxide | water | scandium fluoride molar mass | 20.006 g/mol | 95.977 g/mol | 18.015 g/mol | 101.95112 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -83.36 °C | | 0 °C | 1150 °C boiling point | 19.5 °C | | 99.9839 °C | 1527 °C density | 8.18×10^-4 g/cm^3 (at 25 °C) | | 1 g/cm^3 | 2.52 g/cm^3 solubility in water | miscible | | | surface tension | | | 0.0728 N/m | dynamic viscosity | 1.2571×10^-5 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

Random Queries

H2S + H3AsO3 = H2O + As2S3
freezing point of N-propanol vs isopropanol
CAS number of aluminium, compound with barium (4:1)
chemical types of halothane
alternate names of nickel(II) fluoborate
chemical types tetrahydrofuran
van der Waals radius magnesium
H-bond acceptor thallium(III) nitrate
chemical uses of aluminum cerium oxide
HF + HCCl3 = HCl + HCF2Cl