Input interpretation
![1-propanol-3, 3, 3-d 3 | molar mass](../image_source/afe6cfd225934cf525483751237f5d69.png)
1-propanol-3, 3, 3-d 3 | molar mass
Result
![Find the molar mass, M, for 1-propanol-3, 3, 3-d 3: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CD_3CH_2CH_2OH Use the chemical formula, CD_3CH_2CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 18 H (hydrogen) | 23 I (iodine) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 18 | 12.011 H (hydrogen) | 23 | 1.008 I (iodine) | 1 | 126.90447 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 18 | 12.011 | 18 × 12.011 = 216.198 H (hydrogen) | 23 | 1.008 | 23 × 1.008 = 23.184 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 216.198 g/mol + 23.184 g/mol + 126.90447 g/mol + 31.998 g/mol = 398.284 g/mol](../image_source/d45c2d51029d1f5c587cd3daaf6ab8ac.png)
Find the molar mass, M, for 1-propanol-3, 3, 3-d 3: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CD_3CH_2CH_2OH Use the chemical formula, CD_3CH_2CH_2OH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 18 H (hydrogen) | 23 I (iodine) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 18 | 12.011 H (hydrogen) | 23 | 1.008 I (iodine) | 1 | 126.90447 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 18 | 12.011 | 18 × 12.011 = 216.198 H (hydrogen) | 23 | 1.008 | 23 × 1.008 = 23.184 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 216.198 g/mol + 23.184 g/mol + 126.90447 g/mol + 31.998 g/mol = 398.284 g/mol
Unit conversion
![0.39828 kg/mol (kilograms per mole)](../image_source/93fbd729316abf924b6d7b091bc3fc7d.png)
0.39828 kg/mol (kilograms per mole)
Comparisons
![≈ 0.55 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/924265d3c50a153a13d057625a9ed55b.png)
≈ 0.55 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3427684165b7cd963af32ef87e2466dc.png)
≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/c6058c6d2f265e22929e990be0258769.png)
≈ 6.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.6×10^-22 grams | 6.6×10^-25 kg (kilograms) | 398 u (unified atomic mass units) | 398 Da (daltons)](../image_source/0dbb8eb41deb3aa123a3a682e728e933.png)
Mass of a molecule m from m = M/N_A: | 6.6×10^-22 grams | 6.6×10^-25 kg (kilograms) | 398 u (unified atomic mass units) | 398 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 398](../image_source/a2120338be6791d01d3447eb7f7c588b.png)
Relative molecular mass M_r from M_r = M_u/M: | 398