Input interpretation
D-glucose-13 C6 | orbital hybridization
Result
First draw the structure diagram for D-glucose-13 C6, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Now assign the hybridization for each atom: Answer: | |
Chemical names and formulas
formula | ^13C_6H_12O_6 Hill formula | (13C)_6H_12O_6 name | D-glucose-13 C6 IUPAC name | (2S, 3R, 4S, 5S, 6R)-6-(hydroxymethyl)tetrahydropyran-2, 3, 4, 5-tetrol alternate names | (2S, 3R, 4S, 5S, 6R)-6-(hydroxymethyl)oxane-2, 3, 4, 5-tetrol | (2S, 3R, 4S, 5S, 6R)-6-(hydroxymethyl)tetrahydropyran-2, 3, 4, 5-tetrol | dextrose-13C6 | D-glucose-ul-13C mass fractions | O (oxygen) 0.516% | C (carbon) 0.419% | H (hydrogen) 0.065%