Input interpretation
![sodium dihydrogen citrate | molar mass](../image_source/6844289fc2d3260f20cb736db61835f5.png)
sodium dihydrogen citrate | molar mass
Result
![Find the molar mass, M, for sodium dihydrogen citrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HOC(COONa)(CH_2COOH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 7 Na (sodium) | 1 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 7 | 1.008 Na (sodium) | 1 | 22.98976928 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 72.066 g/mol + 7.056 g/mol + 22.98976928 g/mol + 111.993 g/mol = 214.105 g/mol](../image_source/574f0d0402f2ad217a12f59e490ec56d.png)
Find the molar mass, M, for sodium dihydrogen citrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HOC(COONa)(CH_2COOH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 7 Na (sodium) | 1 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 7 | 1.008 Na (sodium) | 1 | 22.98976928 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 72.066 g/mol + 7.056 g/mol + 22.98976928 g/mol + 111.993 g/mol = 214.105 g/mol
Unit conversion
![0.2141 kg/mol (kilograms per mole)](../image_source/d9b6ea5f92ea523e868c2d632dd1393f.png)
0.2141 kg/mol (kilograms per mole)
Comparisons
![≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/475864291d9f2051ed2c747ffa7f45f6.png)
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/0610e6a8e66a3ccc9e663ac5f7aebce1.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/6a2119d80642b4390041a9ddc2811e89.png)
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 214 u (unified atomic mass units) | 214 Da (daltons)](../image_source/a2e845e596df0de4e0594c6543a812bf.png)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 214 u (unified atomic mass units) | 214 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 214](../image_source/bd60ed8e2a276a8556db93bf24ee9846.png)
Relative molecular mass M_r from M_r = M_u/M: | 214