Input interpretation
diatrizoate | molar mass
Result
Find the molar mass, M, for diatrizoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_9I_3N_2O_4 Use the chemical formula, C_11H_9I_3N_2O_4, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 H (hydrogen) | 9 I (iodine) | 3 N (nitrogen) | 2 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 H (hydrogen) | 9 | 1.008 I (iodine) | 3 | 126.90447 N (nitrogen) | 2 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 I (iodine) | 3 | 126.90447 | 3 × 126.90447 = 380.71341 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 132.121 g/mol + 9.072 g/mol + 380.71341 g/mol + 28.014 g/mol + 63.996 g/mol = 613.916 g/mol
Unit conversion
0.61392 kg/mol (kilograms per mole)
Comparisons
≈ 0.85 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1×10^-21 grams | 1×10^-24 kg (kilograms) | 614 u (unified atomic mass units) | 614 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 614