Input interpretation
sodium azide ⟶ nitrogen + sodium
Balanced equation
Balance the chemical equation algebraically: ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 ⟶ c_2 + c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for N and Na: N: | 3 c_1 = 2 c_2 Na: | c_1 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3/2 c_3 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 3 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 ⟶ 3 + 2
Structures
⟶ +
Names
sodium azide ⟶ nitrogen + sodium
Reaction thermodynamics
Enthalpy
| sodium azide | nitrogen | sodium molecular enthalpy | 21.7 kJ/mol | 0 kJ/mol | 0 kJ/mol total enthalpy | 43.4 kJ/mol | 0 kJ/mol | 0 kJ/mol | H_initial = 43.4 kJ/mol | H_final = 0 kJ/mol | ΔH_rxn^0 | 0 kJ/mol - 43.4 kJ/mol = -43.4 kJ/mol (exothermic) | |
Chemical names and formulas
| sodium azide | nitrogen | sodium Hill formula | N_3Na | N_2 | Na name | sodium azide | nitrogen | sodium IUPAC name | | molecular nitrogen | sodium
Substance properties
| sodium azide | nitrogen | sodium molar mass | 65.011 g/mol | 28.014 g/mol | 22.98976928 g/mol phase | solid (at STP) | gas (at STP) | solid (at STP) melting point | 275 °C | -210 °C | 97.8 °C boiling point | | -195.79 °C | 883 °C density | 1.85 g/cm^3 | 0.001251 g/cm^3 (at 0 °C) | 0.968 g/cm^3 solubility in water | | insoluble | decomposes surface tension | | 0.0066 N/m | dynamic viscosity | | 1.78×10^-5 Pa s (at 25 °C) | 1.413×10^-5 Pa s (at 527 °C) odor | odorless | odorless |
Units
