Search

molar mass of bismuth(III) nitrate pentahydrate vs bismuth(III) nitrate pentahydrate

Input interpretation

bismuth(III) nitrate pentahydrate | molar mass
bismuth(III) nitrate pentahydrate | molar mass

Result

Find the molar mass, M, for bismuth(III) nitrate pentahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Bi(NO_3)_3·5H_2O Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Bi (bismuth) | 1  H (hydrogen) | 10  N (nitrogen) | 3  O (oxygen) | 14 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Bi (bismuth) | 1 | 208.98040  H (hydrogen) | 10 | 1.008  N (nitrogen) | 3 | 14.007  O (oxygen) | 14 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Bi (bismuth) | 1 | 208.98040 | 1 × 208.98040 = 208.98040  H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080  N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021  O (oxygen) | 14 | 15.999 | 14 × 15.999 = 223.986  M = 208.98040 g/mol + 10.080 g/mol + 42.021 g/mol + 223.986 g/mol = 485.067 g/mol
Find the molar mass, M, for bismuth(III) nitrate pentahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Bi(NO_3)_3·5H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Bi (bismuth) | 1 H (hydrogen) | 10 N (nitrogen) | 3 O (oxygen) | 14 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Bi (bismuth) | 1 | 208.98040 H (hydrogen) | 10 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 14 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Bi (bismuth) | 1 | 208.98040 | 1 × 208.98040 = 208.98040 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 14 | 15.999 | 14 × 15.999 = 223.986 M = 208.98040 g/mol + 10.080 g/mol + 42.021 g/mol + 223.986 g/mol = 485.067 g/mol

Unit conversion

0.48507 kg/mol (kilograms per mole)
0.48507 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.67 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.67 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 8.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 8.3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 8.1×10^-22 grams  | 8.1×10^-25 kg (kilograms)  | 485 u (unified atomic mass units)  | 485 Da (daltons)
Mass of a molecule m from m = M/N_A: | 8.1×10^-22 grams | 8.1×10^-25 kg (kilograms) | 485 u (unified atomic mass units) | 485 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 485
Relative molecular mass M_r from M_r = M_u/M: | 485