Input interpretation
![O_2 oxygen + Fe iron ⟶ Fe3O](../image_source/2b8bd17e2586b8898996d04f81c4dcdc.png)
O_2 oxygen + Fe iron ⟶ Fe3O
Balanced equation
![Balance the chemical equation algebraically: O_2 + Fe ⟶ Fe3O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 Fe ⟶ c_3 Fe3O Set the number of atoms in the reactants equal to the number of atoms in the products for O and Fe: O: | 2 c_1 = c_3 Fe: | c_2 = 3 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 6 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | O_2 + 6 Fe ⟶ 2 Fe3O](../image_source/05916266c94a8bfb77b3394ddc1d820d.png)
Balance the chemical equation algebraically: O_2 + Fe ⟶ Fe3O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 Fe ⟶ c_3 Fe3O Set the number of atoms in the reactants equal to the number of atoms in the products for O and Fe: O: | 2 c_1 = c_3 Fe: | c_2 = 3 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 6 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | O_2 + 6 Fe ⟶ 2 Fe3O
Structures
![+ ⟶ Fe3O](../image_source/b52f2828bc0505e82a8337d5eab10497.png)
+ ⟶ Fe3O
Names
![oxygen + iron ⟶ Fe3O](../image_source/dbfda482a1130b740ffb16940d0cae69.png)
oxygen + iron ⟶ Fe3O
Equilibrium constant
![Construct the equilibrium constant, K, expression for: O_2 + Fe ⟶ Fe3O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: O_2 + 6 Fe ⟶ 2 Fe3O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 1 | -1 Fe | 6 | -6 Fe3O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 1 | -1 | ([O2])^(-1) Fe | 6 | -6 | ([Fe])^(-6) Fe3O | 2 | 2 | ([Fe3O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-1) ([Fe])^(-6) ([Fe3O])^2 = ([Fe3O])^2/([O2] ([Fe])^6)](../image_source/b957c4f511f86e0965bbe8cf5fe0e848.png)
Construct the equilibrium constant, K, expression for: O_2 + Fe ⟶ Fe3O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: O_2 + 6 Fe ⟶ 2 Fe3O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 1 | -1 Fe | 6 | -6 Fe3O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 1 | -1 | ([O2])^(-1) Fe | 6 | -6 | ([Fe])^(-6) Fe3O | 2 | 2 | ([Fe3O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-1) ([Fe])^(-6) ([Fe3O])^2 = ([Fe3O])^2/([O2] ([Fe])^6)
Rate of reaction
![Construct the rate of reaction expression for: O_2 + Fe ⟶ Fe3O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: O_2 + 6 Fe ⟶ 2 Fe3O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 1 | -1 Fe | 6 | -6 Fe3O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 1 | -1 | -(Δ[O2])/(Δt) Fe | 6 | -6 | -1/6 (Δ[Fe])/(Δt) Fe3O | 2 | 2 | 1/2 (Δ[Fe3O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[O2])/(Δt) = -1/6 (Δ[Fe])/(Δt) = 1/2 (Δ[Fe3O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/249372e8bcb3895029e90204c0b57ad3.png)
Construct the rate of reaction expression for: O_2 + Fe ⟶ Fe3O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: O_2 + 6 Fe ⟶ 2 Fe3O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 1 | -1 Fe | 6 | -6 Fe3O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 1 | -1 | -(Δ[O2])/(Δt) Fe | 6 | -6 | -1/6 (Δ[Fe])/(Δt) Fe3O | 2 | 2 | 1/2 (Δ[Fe3O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[O2])/(Δt) = -1/6 (Δ[Fe])/(Δt) = 1/2 (Δ[Fe3O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| oxygen | iron | Fe3O formula | O_2 | Fe | Fe3O name | oxygen | iron | IUPAC name | molecular oxygen | iron |](../image_source/ed36c60ed15a39e475c654f9644ac53c.png)
| oxygen | iron | Fe3O formula | O_2 | Fe | Fe3O name | oxygen | iron | IUPAC name | molecular oxygen | iron |
Substance properties
![| oxygen | iron | Fe3O molar mass | 31.998 g/mol | 55.845 g/mol | 183.53 g/mol phase | gas (at STP) | solid (at STP) | melting point | -218 °C | 1535 °C | boiling point | -183 °C | 2750 °C | density | 0.001429 g/cm^3 (at 0 °C) | 7.874 g/cm^3 | solubility in water | | insoluble | surface tension | 0.01347 N/m | | dynamic viscosity | 2.055×10^-5 Pa s (at 25 °C) | | odor | odorless | |](../image_source/9a5564bd3df8485ffc6ba0b70ad7e832.png)
| oxygen | iron | Fe3O molar mass | 31.998 g/mol | 55.845 g/mol | 183.53 g/mol phase | gas (at STP) | solid (at STP) | melting point | -218 °C | 1535 °C | boiling point | -183 °C | 2750 °C | density | 0.001429 g/cm^3 (at 0 °C) | 7.874 g/cm^3 | solubility in water | | insoluble | surface tension | 0.01347 N/m | | dynamic viscosity | 2.055×10^-5 Pa s (at 25 °C) | | odor | odorless | |
Units