Input interpretation
sulfuric acid + hydrogen peroxide + potassium iodate ⟶ water + oxygen + potassium sulfate + iodine
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, I and K: H: | 2 c_1 + 2 c_2 = 2 c_4 O: | 4 c_1 + 2 c_2 + 3 c_3 = c_4 + 2 c_5 + 4 c_6 S: | c_1 = c_6 I: | c_3 = 2 c_7 K: | c_3 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_3 = 2 c_4 = c_2 + 1 c_5 = c_2/2 + 5/2 c_6 = 1 c_7 = 1 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_2 = 1 and solve for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 3 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + + 2 ⟶ 2 + 3 + +
Structures
+ + ⟶ + + +
Names
sulfuric acid + hydrogen peroxide + potassium iodate ⟶ water + oxygen + potassium sulfate + iodine
Chemical names and formulas
| sulfuric acid | hydrogen peroxide | potassium iodate | water | oxygen | potassium sulfate | iodine Hill formula | H_2O_4S | H_2O_2 | IKO_3 | H_2O | O_2 | K_2O_4S | I_2 name | sulfuric acid | hydrogen peroxide | potassium iodate | water | oxygen | potassium sulfate | iodine IUPAC name | sulfuric acid | hydrogen peroxide | potassium iodate | water | molecular oxygen | dipotassium sulfate | molecular iodine