Input interpretation
fluoroantimonic acid | molar mass
Result
Find the molar mass, M, for fluoroantimonic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HSbF_6 Use the chemical formula, HSbF_6, to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 H (hydrogen) | 1 Sb (antimony) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 6 | 18.998403163 H (hydrogen) | 1 | 1.008 Sb (antimony) | 1 | 121.760 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 Sb (antimony) | 1 | 121.760 | 1 × 121.760 = 121.760 M = 113.990418978 g/mol + 1.008 g/mol + 121.760 g/mol = 236.758 g/mol
Unit conversion
0.236758 kg/mol (kilograms per mole)
Comparisons
≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.9×10^-22 grams | 3.9×10^-25 kg (kilograms) | 237 u (unified atomic mass units) | 237 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 237