I2 + Fe = FeI2

I_2 iodine + Fe iron ⟶ FeI_2 ferrous iodide

Balance the chemical equation algebraically: I_2 + Fe ⟶ FeI_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 I_2 + c_2 Fe ⟶ c_3 FeI_2 Set the number of atoms in the reactants equal to the number of atoms in the products for I and Fe: I: | 2 c_1 = 2 c_3 Fe: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | I_2 + Fe ⟶ FeI_2

+ ⟶

iodine + iron ⟶ ferrous iodide

Construct the equilibrium constant, K, expression for: I_2 + Fe ⟶ FeI_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: I_2 + Fe ⟶ FeI_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 1 | -1 Fe | 1 | -1 FeI_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression I_2 | 1 | -1 | ([I2])^(-1) Fe | 1 | -1 | ([Fe])^(-1) FeI_2 | 1 | 1 | [FeI2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([I2])^(-1) ([Fe])^(-1) [FeI2] = ([FeI2])/([I2] [Fe])

Construct the rate of reaction expression for: I_2 + Fe ⟶ FeI_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: I_2 + Fe ⟶ FeI_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 1 | -1 Fe | 1 | -1 FeI_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term I_2 | 1 | -1 | -(Δ[I2])/(Δt) Fe | 1 | -1 | -(Δ[Fe])/(Δt) FeI_2 | 1 | 1 | (Δ[FeI2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[I2])/(Δt) = -(Δ[Fe])/(Δt) = (Δ[FeI2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| iodine | iron | ferrous iodide formula | I_2 | Fe | FeI_2 name | iodine | iron | ferrous iodide IUPAC name | molecular iodine | iron | diiodoiron

| iodine | iron | ferrous iodide molar mass | 253.80894 g/mol | 55.845 g/mol | 309.654 g/mol phase | solid (at STP) | solid (at STP) | melting point | 113 °C | 1535 °C | boiling point | 184 °C | 2750 °C | density | 4.94 g/cm^3 | 7.874 g/cm^3 | 5.32 g/cm^3 solubility in water | | insoluble | slightly soluble dynamic viscosity | 0.00227 Pa s (at 116 °C) | |