Input interpretation
carbon monoxide + zinc oxide ⟶ carbon dioxide + zinc
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for C, O and Zn: C: | c_1 = c_3 O: | c_1 + c_2 = 2 c_3 Zn: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + ⟶ +
Structures
+ ⟶ +
Names
carbon monoxide + zinc oxide ⟶ carbon dioxide + zinc
Reaction thermodynamics
Enthalpy
| carbon monoxide | zinc oxide | carbon dioxide | zinc molecular enthalpy | -110.5 kJ/mol | -350.5 kJ/mol | -393.5 kJ/mol | 0 kJ/mol total enthalpy | -110.5 kJ/mol | -350.5 kJ/mol | -393.5 kJ/mol | 0 kJ/mol | H_initial = -461 kJ/mol | | H_final = -393.5 kJ/mol | ΔH_rxn^0 | -393.5 kJ/mol - -461 kJ/mol = 67.5 kJ/mol (endothermic) | | |
Entropy
| carbon monoxide | zinc oxide | carbon dioxide | zinc molecular entropy | 198 J/(mol K) | 44 J/(mol K) | 214 J/(mol K) | 42 J/(mol K) total entropy | 198 J/(mol K) | 44 J/(mol K) | 214 J/(mol K) | 42 J/(mol K) | S_initial = 242 J/(mol K) | | S_final = 256 J/(mol K) | ΔS_rxn^0 | 256 J/(mol K) - 242 J/(mol K) = 14 J/(mol K) (endoentropic) | | |
Chemical names and formulas
| carbon monoxide | zinc oxide | carbon dioxide | zinc Hill formula | CO | OZn | CO_2 | Zn name | carbon monoxide | zinc oxide | carbon dioxide | zinc IUPAC name | carbon monoxide | oxozinc | carbon dioxide | zinc