Search

selenium tetrabromide

Input interpretation

selenium tetrabromide
selenium tetrabromide

Chemical names and formulas

formula | SeBr_4 Hill formula | Br_4Se name | selenium tetrabromide alternate names | selenium(IV) bromide mass fractions | Br (bromine) 80.2% | Se (selenium) 19.8%
formula | SeBr_4 Hill formula | Br_4Se name | selenium tetrabromide alternate names | selenium(IV) bromide mass fractions | Br (bromine) 80.2% | Se (selenium) 19.8%

Lewis structure

Draw the Lewis structure of selenium tetrabromide. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the bromine (n_Br, val = 7) and selenium (n_Se, val = 6) atoms: 4 n_Br, val + n_Se, val = 34 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8) and selenium (n_Se, full = 8): 4 n_Br, full + n_Se, full = 40 Subtracting these two numbers shows that 40 - 34 = 6 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of selenium has been expanded. After accounting for the expanded valence, there are 4 bonds and hence 8 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 34 - 8 = 26 electrons left to draw: Answer: |   |
Draw the Lewis structure of selenium tetrabromide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the bromine (n_Br, val = 7) and selenium (n_Se, val = 6) atoms: 4 n_Br, val + n_Se, val = 34 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8) and selenium (n_Se, full = 8): 4 n_Br, full + n_Se, full = 40 Subtracting these two numbers shows that 40 - 34 = 6 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of selenium has been expanded. After accounting for the expanded valence, there are 4 bonds and hence 8 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 34 - 8 = 26 electrons left to draw: Answer: | |

Basic properties

molar mass | 398.59 g/mol phase | solid (at STP) melting point | 75 °C density | 4.029 g/cm^3
molar mass | 398.59 g/mol phase | solid (at STP) melting point | 75 °C density | 4.029 g/cm^3

Units

Solid properties (at STP)

density | 4.029 g/cm^3
density | 4.029 g/cm^3

Units

Chemical identifiers

CAS number | 7789-65-3 PubChem CID number | 82246 PubChem SID number | 24864935 SMILES identifier | [Se](Br)(Br)(Br)Br InChI identifier | InChI=1/Br4Se/c1-5(2, 3)4 MDL number | MFCD00049766
CAS number | 7789-65-3 PubChem CID number | 82246 PubChem SID number | 24864935 SMILES identifier | [Se](Br)(Br)(Br)Br InChI identifier | InChI=1/Br4Se/c1-5(2, 3)4 MDL number | MFCD00049766