Search

H3PO4 + Pb = H2 + Pb3(PO4)2

Input interpretation

H_3PO_4 phosphoric acid + Pb lead ⟶ H_2 hydrogen + Pb_3(PO_4)_2 lead(II) phosphate
H_3PO_4 phosphoric acid + Pb lead ⟶ H_2 hydrogen + Pb_3(PO_4)_2 lead(II) phosphate

Balanced equation

Balance the chemical equation algebraically: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_3PO_4 + c_2 Pb ⟶ c_3 H_2 + c_4 Pb_3(PO_4)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P and Pb: H: | 3 c_1 = 2 c_3 O: | 4 c_1 = 8 c_4 P: | c_1 = 2 c_4 Pb: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2
Balance the chemical equation algebraically: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_3PO_4 + c_2 Pb ⟶ c_3 H_2 + c_4 Pb_3(PO_4)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P and Pb: H: | 3 c_1 = 2 c_3 O: | 4 c_1 = 8 c_4 P: | c_1 = 2 c_4 Pb: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2

Structures

+ ⟶ +
+ ⟶ +

Names

phosphoric acid + lead ⟶ hydrogen + lead(II) phosphate
phosphoric acid + lead ⟶ hydrogen + lead(II) phosphate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 2 | -2 Pb | 3 | -3 H_2 | 3 | 3 Pb_3(PO_4)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_3PO_4 | 2 | -2 | ([H3PO4])^(-2) Pb | 3 | -3 | ([Pb])^(-3) H_2 | 3 | 3 | ([H2])^3 Pb_3(PO_4)_2 | 1 | 1 | [Pb3(PO4)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H3PO4])^(-2) ([Pb])^(-3) ([H2])^3 [Pb3(PO4)2] = (([H2])^3 [Pb3(PO4)2])/(([H3PO4])^2 ([Pb])^3)
Construct the equilibrium constant, K, expression for: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 2 | -2 Pb | 3 | -3 H_2 | 3 | 3 Pb_3(PO_4)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_3PO_4 | 2 | -2 | ([H3PO4])^(-2) Pb | 3 | -3 | ([Pb])^(-3) H_2 | 3 | 3 | ([H2])^3 Pb_3(PO_4)_2 | 1 | 1 | [Pb3(PO4)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H3PO4])^(-2) ([Pb])^(-3) ([H2])^3 [Pb3(PO4)2] = (([H2])^3 [Pb3(PO4)2])/(([H3PO4])^2 ([Pb])^3)

Rate of reaction

Construct the rate of reaction expression for: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 2 | -2 Pb | 3 | -3 H_2 | 3 | 3 Pb_3(PO_4)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_3PO_4 | 2 | -2 | -1/2 (Δ[H3PO4])/(Δt) Pb | 3 | -3 | -1/3 (Δ[Pb])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) Pb_3(PO_4)_2 | 1 | 1 | (Δ[Pb3(PO4)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[H3PO4])/(Δt) = -1/3 (Δ[Pb])/(Δt) = 1/3 (Δ[H2])/(Δt) = (Δ[Pb3(PO4)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_3PO_4 + Pb ⟶ H_2 + Pb_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 H_3PO_4 + 3 Pb ⟶ 3 H_2 + Pb_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_3PO_4 | 2 | -2 Pb | 3 | -3 H_2 | 3 | 3 Pb_3(PO_4)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_3PO_4 | 2 | -2 | -1/2 (Δ[H3PO4])/(Δt) Pb | 3 | -3 | -1/3 (Δ[Pb])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) Pb_3(PO_4)_2 | 1 | 1 | (Δ[Pb3(PO4)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[H3PO4])/(Δt) = -1/3 (Δ[Pb])/(Δt) = 1/3 (Δ[H2])/(Δt) = (Δ[Pb3(PO4)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| phosphoric acid | lead | hydrogen | lead(II) phosphate formula | H_3PO_4 | Pb | H_2 | Pb_3(PO_4)_2 Hill formula | H_3O_4P | Pb | H_2 | O_8P_2Pb_3 name | phosphoric acid | lead | hydrogen | lead(II) phosphate IUPAC name | phosphoric acid | lead | molecular hydrogen | lead(+2) cation diphosphate
| phosphoric acid | lead | hydrogen | lead(II) phosphate formula | H_3PO_4 | Pb | H_2 | Pb_3(PO_4)_2 Hill formula | H_3O_4P | Pb | H_2 | O_8P_2Pb_3 name | phosphoric acid | lead | hydrogen | lead(II) phosphate IUPAC name | phosphoric acid | lead | molecular hydrogen | lead(+2) cation diphosphate

Substance properties

| phosphoric acid | lead | hydrogen | lead(II) phosphate molar mass | 97.994 g/mol | 207.2 g/mol | 2.016 g/mol | 811.5 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 42.4 °C | 327.4 °C | -259.2 °C | 1290 °C boiling point | 158 °C | 1740 °C | -252.8 °C | density | 1.685 g/cm^3 | 11.34 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 6.9 g/cm^3 solubility in water | very soluble | insoluble | | dynamic viscosity | | 0.00183 Pa s (at 38 °C) | 8.9×10^-6 Pa s (at 25 °C) | odor | odorless | | odorless |
| phosphoric acid | lead | hydrogen | lead(II) phosphate molar mass | 97.994 g/mol | 207.2 g/mol | 2.016 g/mol | 811.5 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 42.4 °C | 327.4 °C | -259.2 °C | 1290 °C boiling point | 158 °C | 1740 °C | -252.8 °C | density | 1.685 g/cm^3 | 11.34 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 6.9 g/cm^3 solubility in water | very soluble | insoluble | | dynamic viscosity | | 0.00183 Pa s (at 38 °C) | 8.9×10^-6 Pa s (at 25 °C) | odor | odorless | | odorless |

Units

Random Queries

formula of 1,2,4-trichlorobenzene
H2O + Na2CO3 + Al2(SO4)3 = CO2 + Na2SO4 + Al(OH)3
(+/-)-sodium camphorsulfonate
boiling point of 2-pentyl isocyanide
molar mass of zinc hydroxide
molar mass of hydrogen chloride vs perchloric acid
non-standard isotope tally of lead(IV) acetate
total number of protons of cobalt(III) ions
S + KOH = H2O + K2S + K2S2O3
alternate names of tantalum(IV) carbide vs osmium