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H2O + K2CO3 = KOH + H2CO3

Input interpretation

H_2O water + K_2CO_3 pearl ash ⟶ KOH potassium hydroxide + H_2CO_3 carbonic acid
H_2O water + K_2CO_3 pearl ash ⟶ KOH potassium hydroxide + H_2CO_3 carbonic acid

Balanced equation

Balance the chemical equation algebraically: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 K_2CO_3 ⟶ c_3 KOH + c_4 H_2CO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, C and K: H: | 2 c_1 = c_3 + 2 c_4 O: | c_1 + 3 c_2 = c_3 + 3 c_4 C: | c_2 = c_4 K: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3
Balance the chemical equation algebraically: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 K_2CO_3 ⟶ c_3 KOH + c_4 H_2CO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, C and K: H: | 2 c_1 = c_3 + 2 c_4 O: | c_1 + 3 c_2 = c_3 + 3 c_4 C: | c_2 = c_4 K: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3

Structures

+ ⟶ +
+ ⟶ +

Names

water + pearl ash ⟶ potassium hydroxide + carbonic acid
water + pearl ash ⟶ potassium hydroxide + carbonic acid

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 2 | -2 K_2CO_3 | 1 | -1 KOH | 2 | 2 H_2CO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 2 | -2 | ([H2O])^(-2) K_2CO_3 | 1 | -1 | ([K2CO3])^(-1) KOH | 2 | 2 | ([KOH])^2 H_2CO_3 | 1 | 1 | [H2CO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-2) ([K2CO3])^(-1) ([KOH])^2 [H2CO3] = (([KOH])^2 [H2CO3])/(([H2O])^2 [K2CO3])
Construct the equilibrium constant, K, expression for: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 2 | -2 K_2CO_3 | 1 | -1 KOH | 2 | 2 H_2CO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 2 | -2 | ([H2O])^(-2) K_2CO_3 | 1 | -1 | ([K2CO3])^(-1) KOH | 2 | 2 | ([KOH])^2 H_2CO_3 | 1 | 1 | [H2CO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-2) ([K2CO3])^(-1) ([KOH])^2 [H2CO3] = (([KOH])^2 [H2CO3])/(([H2O])^2 [K2CO3])

Rate of reaction

Construct the rate of reaction expression for: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 2 | -2 K_2CO_3 | 1 | -1 KOH | 2 | 2 H_2CO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 2 | -2 | -1/2 (Δ[H2O])/(Δt) K_2CO_3 | 1 | -1 | -(Δ[K2CO3])/(Δt) KOH | 2 | 2 | 1/2 (Δ[KOH])/(Δt) H_2CO_3 | 1 | 1 | (Δ[H2CO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[H2O])/(Δt) = -(Δ[K2CO3])/(Δt) = 1/2 (Δ[KOH])/(Δt) = (Δ[H2CO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + K_2CO_3 ⟶ KOH + H_2CO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 H_2O + K_2CO_3 ⟶ 2 KOH + H_2CO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 2 | -2 K_2CO_3 | 1 | -1 KOH | 2 | 2 H_2CO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 2 | -2 | -1/2 (Δ[H2O])/(Δt) K_2CO_3 | 1 | -1 | -(Δ[K2CO3])/(Δt) KOH | 2 | 2 | 1/2 (Δ[KOH])/(Δt) H_2CO_3 | 1 | 1 | (Δ[H2CO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[H2O])/(Δt) = -(Δ[K2CO3])/(Δt) = 1/2 (Δ[KOH])/(Δt) = (Δ[H2CO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| water | pearl ash | potassium hydroxide | carbonic acid formula | H_2O | K_2CO_3 | KOH | H_2CO_3 Hill formula | H_2O | CK_2O_3 | HKO | CH_2O_3 name | water | pearl ash | potassium hydroxide | carbonic acid IUPAC name | water | dipotassium carbonate | potassium hydroxide | carbonic acid
| water | pearl ash | potassium hydroxide | carbonic acid formula | H_2O | K_2CO_3 | KOH | H_2CO_3 Hill formula | H_2O | CK_2O_3 | HKO | CH_2O_3 name | water | pearl ash | potassium hydroxide | carbonic acid IUPAC name | water | dipotassium carbonate | potassium hydroxide | carbonic acid

Substance properties

| water | pearl ash | potassium hydroxide | carbonic acid molar mass | 18.015 g/mol | 138.2 g/mol | 56.105 g/mol | 62.024 g/mol phase | liquid (at STP) | solid (at STP) | solid (at STP) | melting point | 0 °C | 891 °C | 406 °C | boiling point | 99.9839 °C | | 1327 °C | density | 1 g/cm^3 | 2.43 g/cm^3 | 2.044 g/cm^3 | solubility in water | | soluble | soluble | surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 0.001 Pa s (at 550 °C) | odor | odorless | | |
| water | pearl ash | potassium hydroxide | carbonic acid molar mass | 18.015 g/mol | 138.2 g/mol | 56.105 g/mol | 62.024 g/mol phase | liquid (at STP) | solid (at STP) | solid (at STP) | melting point | 0 °C | 891 °C | 406 °C | boiling point | 99.9839 °C | | 1327 °C | density | 1 g/cm^3 | 2.43 g/cm^3 | 2.044 g/cm^3 | solubility in water | | soluble | soluble | surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 0.001 Pa s (at 550 °C) | odor | odorless | | |

Units

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