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NaOH + NaHSO4 = H2O + Na2SO4

Input interpretation

NaOH sodium hydroxide + NaHSO_4 sodium bisulfate ⟶ H_2O water + Na_2SO_4 sodium sulfate
NaOH sodium hydroxide + NaHSO_4 sodium bisulfate ⟶ H_2O water + Na_2SO_4 sodium sulfate

Balanced equation

Balance the chemical equation algebraically: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 NaHSO_4 ⟶ c_3 H_2O + c_4 Na_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and S: H: | c_1 + c_2 = 2 c_3 Na: | c_1 + c_2 = 2 c_4 O: | c_1 + 4 c_2 = c_3 + 4 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4
Balance the chemical equation algebraically: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 NaHSO_4 ⟶ c_3 H_2O + c_4 Na_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and S: H: | c_1 + c_2 = 2 c_3 Na: | c_1 + c_2 = 2 c_4 O: | c_1 + 4 c_2 = c_3 + 4 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4

Structures

 + ⟶ +
+ ⟶ +

Names

sodium hydroxide + sodium bisulfate ⟶ water + sodium sulfate
sodium hydroxide + sodium bisulfate ⟶ water + sodium sulfate

Reaction thermodynamics

Enthalpy

 | sodium hydroxide | sodium bisulfate | water | sodium sulfate molecular enthalpy | -425.8 kJ/mol | -1126 kJ/mol | -285.8 kJ/mol | -1387 kJ/mol total enthalpy | -425.8 kJ/mol | -1126 kJ/mol | -285.8 kJ/mol | -1387 kJ/mol  | H_initial = -1551 kJ/mol | | H_final = -1673 kJ/mol |  ΔH_rxn^0 | -1673 kJ/mol - -1551 kJ/mol = -121.6 kJ/mol (exothermic) | | |
| sodium hydroxide | sodium bisulfate | water | sodium sulfate molecular enthalpy | -425.8 kJ/mol | -1126 kJ/mol | -285.8 kJ/mol | -1387 kJ/mol total enthalpy | -425.8 kJ/mol | -1126 kJ/mol | -285.8 kJ/mol | -1387 kJ/mol | H_initial = -1551 kJ/mol | | H_final = -1673 kJ/mol | ΔH_rxn^0 | -1673 kJ/mol - -1551 kJ/mol = -121.6 kJ/mol (exothermic) | | |

Gibbs free energy

 | sodium hydroxide | sodium bisulfate | water | sodium sulfate molecular free energy | -379.7 kJ/mol | -992.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol total free energy | -379.7 kJ/mol | -992.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol  | G_initial = -1373 kJ/mol | | G_final = -1507 kJ/mol |  ΔG_rxn^0 | -1507 kJ/mol - -1373 kJ/mol = -134.8 kJ/mol (exergonic) | | |
| sodium hydroxide | sodium bisulfate | water | sodium sulfate molecular free energy | -379.7 kJ/mol | -992.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol total free energy | -379.7 kJ/mol | -992.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol | G_initial = -1373 kJ/mol | | G_final = -1507 kJ/mol | ΔG_rxn^0 | -1507 kJ/mol - -1373 kJ/mol = -134.8 kJ/mol (exergonic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 NaHSO_4 | 1 | -1 H_2O | 1 | 1 Na_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 1 | -1 | ([NaOH])^(-1) NaHSO_4 | 1 | -1 | ([NaHSO4])^(-1) H_2O | 1 | 1 | [H2O] Na_2SO_4 | 1 | 1 | [Na2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([NaOH])^(-1) ([NaHSO4])^(-1) [H2O] [Na2SO4] = ([H2O] [Na2SO4])/([NaOH] [NaHSO4])
Construct the equilibrium constant, K, expression for: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 NaHSO_4 | 1 | -1 H_2O | 1 | 1 Na_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 1 | -1 | ([NaOH])^(-1) NaHSO_4 | 1 | -1 | ([NaHSO4])^(-1) H_2O | 1 | 1 | [H2O] Na_2SO_4 | 1 | 1 | [Na2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-1) ([NaHSO4])^(-1) [H2O] [Na2SO4] = ([H2O] [Na2SO4])/([NaOH] [NaHSO4])

Rate of reaction

Construct the rate of reaction expression for: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 NaHSO_4 | 1 | -1 H_2O | 1 | 1 Na_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 1 | -1 | -(Δ[NaOH])/(Δt) NaHSO_4 | 1 | -1 | -(Δ[NaHSO4])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[NaOH])/(Δt) = -(Δ[NaHSO4])/(Δt) = (Δ[H2O])/(Δt) = (Δ[Na2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: NaOH + NaHSO_4 ⟶ H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 NaHSO_4 | 1 | -1 H_2O | 1 | 1 Na_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 1 | -1 | -(Δ[NaOH])/(Δt) NaHSO_4 | 1 | -1 | -(Δ[NaHSO4])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[NaOH])/(Δt) = -(Δ[NaHSO4])/(Δt) = (Δ[H2O])/(Δt) = (Δ[Na2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | sodium hydroxide | sodium bisulfate | water | sodium sulfate formula | NaOH | NaHSO_4 | H_2O | Na_2SO_4 Hill formula | HNaO | HNaO_4S | H_2O | Na_2O_4S name | sodium hydroxide | sodium bisulfate | water | sodium sulfate IUPAC name | sodium hydroxide | | water | disodium sulfate
| sodium hydroxide | sodium bisulfate | water | sodium sulfate formula | NaOH | NaHSO_4 | H_2O | Na_2SO_4 Hill formula | HNaO | HNaO_4S | H_2O | Na_2O_4S name | sodium hydroxide | sodium bisulfate | water | sodium sulfate IUPAC name | sodium hydroxide | | water | disodium sulfate

Substance properties

 | sodium hydroxide | sodium bisulfate | water | sodium sulfate molar mass | 39.997 g/mol | 120.1 g/mol | 18.015 g/mol | 142.04 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 323 °C | 181.85 °C | 0 °C | 884 °C boiling point | 1390 °C | | 99.9839 °C | 1429 °C density | 2.13 g/cm^3 | 1.8 g/cm^3 | 1 g/cm^3 | 2.68 g/cm^3 solubility in water | soluble | | | soluble surface tension | 0.07435 N/m | | 0.0728 N/m |  dynamic viscosity | 0.004 Pa s (at 350 °C) | | 8.9×10^-4 Pa s (at 25 °C) |  odor | | | odorless |
| sodium hydroxide | sodium bisulfate | water | sodium sulfate molar mass | 39.997 g/mol | 120.1 g/mol | 18.015 g/mol | 142.04 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 323 °C | 181.85 °C | 0 °C | 884 °C boiling point | 1390 °C | | 99.9839 °C | 1429 °C density | 2.13 g/cm^3 | 1.8 g/cm^3 | 1 g/cm^3 | 2.68 g/cm^3 solubility in water | soluble | | | soluble surface tension | 0.07435 N/m | | 0.0728 N/m | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units