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CO2 + Ca(OH)2 = Ca(HCO3)2

Input interpretation

CO_2 carbon dioxide + Ca(OH)_2 calcium hydroxide ⟶ Ca(HCO3)2
CO_2 carbon dioxide + Ca(OH)_2 calcium hydroxide ⟶ Ca(HCO3)2

Balanced equation

Balance the chemical equation algebraically: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 CO_2 + c_2 Ca(OH)_2 ⟶ c_3 Ca(HCO3)2 Set the number of atoms in the reactants equal to the number of atoms in the products for C, O, Ca and H: C: | c_1 = 2 c_3 O: | 2 c_1 + 2 c_2 = 6 c_3 Ca: | c_2 = c_3 H: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2
Balance the chemical equation algebraically: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 CO_2 + c_2 Ca(OH)_2 ⟶ c_3 Ca(HCO3)2 Set the number of atoms in the reactants equal to the number of atoms in the products for C, O, Ca and H: C: | c_1 = 2 c_3 O: | 2 c_1 + 2 c_2 = 6 c_3 Ca: | c_2 = c_3 H: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2

Structures

 + ⟶ Ca(HCO3)2
+ ⟶ Ca(HCO3)2

Names

carbon dioxide + calcium hydroxide ⟶ Ca(HCO3)2
carbon dioxide + calcium hydroxide ⟶ Ca(HCO3)2

Equilibrium constant

Construct the equilibrium constant, K, expression for: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 2 | -2 Ca(OH)_2 | 1 | -1 Ca(HCO3)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression CO_2 | 2 | -2 | ([CO2])^(-2) Ca(OH)_2 | 1 | -1 | ([Ca(OH)2])^(-1) Ca(HCO3)2 | 1 | 1 | [Ca(HCO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([CO2])^(-2) ([Ca(OH)2])^(-1) [Ca(HCO3)2] = ([Ca(HCO3)2])/(([CO2])^2 [Ca(OH)2])
Construct the equilibrium constant, K, expression for: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 2 | -2 Ca(OH)_2 | 1 | -1 Ca(HCO3)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression CO_2 | 2 | -2 | ([CO2])^(-2) Ca(OH)_2 | 1 | -1 | ([Ca(OH)2])^(-1) Ca(HCO3)2 | 1 | 1 | [Ca(HCO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([CO2])^(-2) ([Ca(OH)2])^(-1) [Ca(HCO3)2] = ([Ca(HCO3)2])/(([CO2])^2 [Ca(OH)2])

Rate of reaction

Construct the rate of reaction expression for: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 2 | -2 Ca(OH)_2 | 1 | -1 Ca(HCO3)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term CO_2 | 2 | -2 | -1/2 (Δ[CO2])/(Δt) Ca(OH)_2 | 1 | -1 | -(Δ[Ca(OH)2])/(Δt) Ca(HCO3)2 | 1 | 1 | (Δ[Ca(HCO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[CO2])/(Δt) = -(Δ[Ca(OH)2])/(Δt) = (Δ[Ca(HCO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 CO_2 + Ca(OH)_2 ⟶ Ca(HCO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i CO_2 | 2 | -2 Ca(OH)_2 | 1 | -1 Ca(HCO3)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term CO_2 | 2 | -2 | -1/2 (Δ[CO2])/(Δt) Ca(OH)_2 | 1 | -1 | -(Δ[Ca(OH)2])/(Δt) Ca(HCO3)2 | 1 | 1 | (Δ[Ca(HCO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[CO2])/(Δt) = -(Δ[Ca(OH)2])/(Δt) = (Δ[Ca(HCO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | carbon dioxide | calcium hydroxide | Ca(HCO3)2 formula | CO_2 | Ca(OH)_2 | Ca(HCO3)2 Hill formula | CO_2 | CaH_2O_2 | C2H2CaO6 name | carbon dioxide | calcium hydroxide |  IUPAC name | carbon dioxide | calcium dihydroxide |
| carbon dioxide | calcium hydroxide | Ca(HCO3)2 formula | CO_2 | Ca(OH)_2 | Ca(HCO3)2 Hill formula | CO_2 | CaH_2O_2 | C2H2CaO6 name | carbon dioxide | calcium hydroxide | IUPAC name | carbon dioxide | calcium dihydroxide |

Substance properties

 | carbon dioxide | calcium hydroxide | Ca(HCO3)2 molar mass | 44.009 g/mol | 74.092 g/mol | 162.11 g/mol phase | gas (at STP) | solid (at STP) |  melting point | -56.56 °C (at triple point) | 550 °C |  boiling point | -78.5 °C (at sublimation point) | |  density | 0.00184212 g/cm^3 (at 20 °C) | 2.24 g/cm^3 |  solubility in water | | slightly soluble |  dynamic viscosity | 1.491×10^-5 Pa s (at 25 °C) | |  odor | odorless | odorless |
| carbon dioxide | calcium hydroxide | Ca(HCO3)2 molar mass | 44.009 g/mol | 74.092 g/mol | 162.11 g/mol phase | gas (at STP) | solid (at STP) | melting point | -56.56 °C (at triple point) | 550 °C | boiling point | -78.5 °C (at sublimation point) | | density | 0.00184212 g/cm^3 (at 20 °C) | 2.24 g/cm^3 | solubility in water | | slightly soluble | dynamic viscosity | 1.491×10^-5 Pa s (at 25 °C) | | odor | odorless | odorless |

Units